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Gnoma [55]
4 years ago
12

Descriptive investigations involve collecting data about a system, but not making observations .

Physics
2 answers:
MissTica4 years ago
8 0

Answer:

Descriptive investigations involve collecting data about a system, but not making observations <u>comparisons.</u>

Angelina_Jolie [31]4 years ago
4 0
The correct statement should be: Descriptive investigations involve collecting data about a system, but not making comparisons. 
so i believe the statement above is false

In descriptive investigations, we shall not make any hypothesis for the situation and we just need to fully record all obeservations.
By doing this, we could fully analyze the variables without comparing and manipulating it.

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Two concurrent forces of 6 newtons and 12 newtons could produce the same effect as a single force of?
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If gas in a cylinder is maintained at a constant temperature​ T, the pressure P is related to the volume V by a formula of the f
Mkey [24]

The given question is incomplete. The complete question is as follows.

If gas in a cylinder is maintained at a constant temperature T, the pressure P is related to the volume V by a formula of the form

P = \frac{nRT}{(V - nb)} - \frac{an^2}{V^2}, in which a, b, n, and R are constants. Find \frac{dP}{dV}.

Explanation:

We will use the quotient rule for each of the two terms on the right side as follows.

        P = \frac{nRT}{V - nb} - \frac{an^{2}}{V^{2}}

\frac{dP}{dV} = \frac{0(V - nb) - nRT(1)}{(V - nb)^{2}} - \frac{0(V)^{2} - an^{2}(2V)}{V^{4}}

            = \frac{-nRT}{(V - nb)^{2}} - \frac{-2an^{2}V}{V^{4}}

            = \frac{-nRT}{(V - nb)^{2}} + \frac{2an^{2}}{V^{3}}

            = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}

   \frac{dP}{dV} = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}

Thus, we can conclude that the value of \frac{dP}{dV} = \frac{2an^{2}}{V^{3}} - \frac{nRT}{(V - nb)^{2}}.

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