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3 years ago

Descriptive investigations involve collecting data about a system, but not making observations .

Physics

2 answers:

MissTica3 years ago

8 0

Answer:

Descriptive investigations involve collecting data about a system, but not making observations <u>comparisons.</u>

Angelina_Jolie [31]3 years ago

4 0

The correct statement should be: Descriptive investigations involve collecting data about a system, but not making comparisons.
so i believe the statement above is false

In descriptive investigations, we shall not make any hypothesis for the situation and we just need to fully record all obeservations.
By doing this, we could fully analyze the variables without comparing and manipulating it.

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You move a 75-kg box 35 m. This requires a force of 90 N. how much work is done while moving the box?

Luda [366]

W = F*d.

= 90*35 = 3150J.

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2 years ago

What amount of heat is required to raise the temperature of 25 grams of copper to cause a 15ºC change? The specific heat of copp

Lina20 [59]

The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

$Q=mC\Delta T$

where:

m is the mass of the substance

C is the specific heat capacity of the substance

$\Delta T$ is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

$\Delta T = 15^{\circ}C$ (change in temperature)

Substituting, we find:

$Q=(25)(0.39)(15)=146 J$

So, the closest answer is B) 150 J.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

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3 0

3 years ago

A man stands by a train track to watch the train car go by. Inside, a man walks through the train car eating a hot dog (the hot

antiseptic1488 [7]

Answer:

D) 11 m/s

Explanation:

The problem asks us to calculate the velocity of the hot dog with respect to the observer stationary outside the train. This velocity is given by:

$v=v_t + v_m + v_h$

where

$v_t=+10 m/s$ is the velocity of the train (towards right)

$v_m=+2 m/s$ is the velocity of the man (towards right)

$v_h=-1 m/s$ is the velocity of the hot-dog (towards left, so we put a negative sign)

Substituting the numbers into the equation, we find

$v=+10 m/s+2 m/s-1 m/s=+11 m/s$

and the positive sign means the velocity is toward right.

5 0

3 years ago

Read 2 more answers

The base of a hexagonal prism has an apothem measuring 10 inches and an area of 346.41 square inches. the prism is 12 inches tal

tigry1 [53]

The approximate lateral area of the prism is determined as 831 square inches.

<h3>What is lateral area of the hexagonal prism?</h3>

The lateral area of the hexagonal prism is calculated as follows;

LA = PH

where;

P is perimeter of the prism
H is height

A = ¹/₂Pa

where;

a is apothem = 10 inches
A is base area = 346.41 in²

346.41 = ¹/₂(10)P

346.41 = 5P

P = 346.41/5

P = 69.282 inches

LA = PH

LA = 69.282 x 12

LA = 831.38 in²

Learn more about lateral area of prism here: brainly.com/question/296674

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8 0

2 years ago

A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl

aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i: unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R= 131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

$D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2} }$

$D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2} }$

D₂= 167.21 cm

Direction of the second displacement

$\beta = tan^{-1} \frac{D_{y}}{D_{x} }$

$\beta = tan^{-1} \frac{62.18}{155.22 }$

β= 21.8°

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0

3 years ago