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serg [7]
3 years ago
10

The period of a satellite circling planet Nutron is observed to be 84 s when it is in a circular orbit with a radius of 8.0 x 10

6 m. What is the mass of planet Nutron
Physics
1 answer:
antoniya [11.8K]3 years ago
8 0

Answer:

4.3 * 10^28 kg

Explanation:

Given:

Period, T = 84s

Radius of satellite orbit, r = 8*10^6

Using the relation :

M = 4π²r³ / GT²

Where G = Gravitational constant, 6.67 * 10^-11

M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2

M = (20218.191872 * 10^18) / 47063.52 * 10^-11

M = 0.4295937 * 10^18 - (-11)

M = 0.4295937 * 10^29

M = 4.295937 * 10^28 kg

M = 4.3 * 10^28 kg

Mass of planet Nutron = 4.3 * 10^28 kg

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Total lung capacity of a typical adult is approximately 5.0L. Approximately 20% of the air is oxygen, as air is 20% oxygen. At s
Tresset [83]

Answer:

n=0.03928 moles

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles

Explanation:

The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs

Volume of oxygen in lungs =V=5*20%= 1 L=1*10^{-3} m^3

Temperature=T=37^oC=273+37=310K

Pressure at sea level = P= 1 atm=1.0125*10^5 Pa

R is universal Gas Constant =8.314 J/mol.K

Formula:

n=\frac{PV}{RT}\\n=\frac{(1.0125*10^5) *(1*10^{-3})}{(8.314)*310} \\n=0.03928 mol

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles

8 0
4 years ago
School homework about multiplying fractions <br><br>worth 30 brainly points​
RoseWind [281]

Answer:

Explanation:

1. \frac{1}{3} x \frac{6}{7} = \frac{6}{21}

          = \frac{2}{7}

b. \frac{6}{8} + \frac{4}{9} = \frac{24}{72}

            = \frac{1}{3}

c. \frac{10}{15} x \frac{3}{4} = \frac{30}{60}

            = \frac{1}{2}

d. \frac{7}{10} of \frac{5}{10} = \frac{7}{10} x \frac{5}{10}

                = \frac{35}{100}

                = \frac{7}{20}

e. \frac{3}{8} of \frac{4}{6} = \frac{3}{8} x \frac{4}{6}

            = \frac{12}{48}

            = \frac{1}{4}

f. \frac{7}{12} of \frac{9}{14} = \frac{7}{12} x \frac{9}{14}

              = \frac{63}{168}

              = \frac{3}{8}

2. \frac{22}{6} x \frac{3}{11} = \frac{66}{66}

              = 1

b. \frac{15}{6} x \frac{4}{5} = \frac{60}{30}

             = 2

c. \frac{25}{8} x \frac{4}{10} = \frac{100}{80}

              = \frac{5}{4}

d. \frac{33}{12} x \frac{4}{15} = \frac{132}{180}

             = \frac{11}{15}

4 0
3 years ago
If you push twice as hard against a stationary brick wall, the amount of work you do
Alecsey [184]

Answer:

Zero

Explanation:

The work done on an object is given by:

W=Fd cos \theta

where

F is the force applied on the object

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement

In this problem, you are pushing again a stationary wall: this means that the walls does not move. As a result, the displacement is zero: d=0. Therefore, the work done is also zero: W=0.

8 0
3 years ago
How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.
kenny6666 [7]

Answer:

it's quite difficult

Explanation:

6 0
3 years ago
A resistor converts 350 J of electrical energy to other forms of energy. What is the amount of
Helga [31]

Answer:

50C

Explanation:

Given parameters:

Electrical energy  = 350J

Potential difference  = 7V

Unknown:

Amount of charge = ?

Solution:

To solve this problem, use the expression below;

  E  = q x v

E is the electrical energy

q is the quantity of charge

v is the voltage

Insert the parameters and solve for q;

            350 = q x 7

            q = \frac{350}{7}

             q = 50C

5 0
3 years ago
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