The equation for momentum is p=mv. Which letter represents the momentum? Question 2 options: p m v

Two lightbulbs work on a 120-V circuit One 50 W and the other is 100 W. Which bulb has a higher resistance? Explain pls!!!!

Sladkaya [172]

Answer:

Bulb 1 has more resistance.

Explanation:

Given that,

Two lightbulbs work on a 120-V circuit.

The power of circuit 1, P₁ = 50 W

The power of circuit 2, P₂ = 100 W

We need to find the bulb that has a higher resistance.

The power of the bulb is given by :

$P = \dfrac{V^2}{R}$

For bulb 1,

$R_1=\dfrac{V^2}{P_1}\\\\R_1=\dfrac{(120)^2}{50}\\\\R_1=288\ \Omega$

For bulb 2,

$R_2=\dfrac{V^2}{P_2}\\\\R_2=\dfrac{(120)^2}{100}\\\\R_2=144\ \Omega$

So, bulb 1 has higher resistance.

8 0

2 years ago

In a high school swim competition, a student takes 1.6 s to complete 1.5 somersaults. Determine the average angular speed of the

Rufina [12.5K]

Answer:

The angular speed is $w = 5.89 \ rad/s$

Explanation:

From the question we are told that

The time taken is $t = 1.6 s$

The number of somersaults is n = 1.5

The total angular displacement during the somersault is mathematically represented as

$\theta = n * 2 * \pi$

substituting values

$\theta = 1.5 * 2 * 3.142$

$\theta = 9.426 \ rad$

The angular speed is mathematically represented as

$w = \frac{\theta }{t}$

substituting values

$w = \frac{9.426}{1.6}$

$w = 5.89 \ rad/s$

3 0

3 years ago

Which of the following types of radiation can penetrate through paper but not through wood?

andrew-mc [135]

The type of radiation that can penetrate through paper, but not through wood is called beta rays. Beta rays can penetrate paper and air, but a thin piece of alimony can stop it. Gamma can cut through anything except lead and many inches of concrete. Alpha can be stopped by paper and not penetrated. The correct answer is B.

4 0

3 years ago

Read 2 more answers

The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

puteri [66]

Answer:

$t=5.3687\ s$ is the time taken by the car to accelerate the desired range of the speed from zero at full power.