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Eva8 [605]
4 years ago
13

He discovered that the orbits of planets are ellipses.

Physics
2 answers:
bezimeni [28]4 years ago
6 0

Answer:

Kepler

Explanation:

Kepler discovered that the orbits of planets are ellipses.

Alenkinab [10]4 years ago
6 0

<em>Johannes Kepler</em>, the Polish mathematician, discovered that the planetary orbits ARE most likely ellipses.

Isaac Newton, the English Physicist/mathematician, discovered that the planetary orbits HAVE TO BE ellipses.

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A radioactive nucleus has a half-life of 5*108 years. Assuming that a sample of rock (say, in an asteroid) solidified right afte
Gre4nikov [31]

Answer:

0.002

Explanation:

The half-life of the radioactive nucleus is related to its quantity, by the following equation:

N_{t} = N_{0}2^{-t/t_{1/2}}

<u>Where:</u>

<em>N(t): is the quantity of the radioactive nucleus at time t</em>

<em>N₀: is the  initial quantity of the radioactive nucleus</em>

<em>t: is the time = 4.5x10⁹ years</em>

<em>t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years</em>

\frac{N_{t}}{N_{0}} = 2^{-4.5 \cdot 10^{9} y/5 \cdot 10^{8} y} = 2 \cdot 10^{-3}

Therefore, the fraction of the radioactive element in the rock today is 0.002.

I hope it helps you!  

7 0
4 years ago
How does a person standing on the ground correctly explain why you, sitting on the left side of a slippery back car seat, slide
Korvikt [17]

Answer:

if the car is traveling north, the person is also traveling north,

If the car turns to (left) to the west, the person will still tend to travel to the north and will slide to the right (north) on a slippery car seat.

5 0
2 years ago
Consider 3.5 kg of austenite containing 0.95 wt% c and cooled to below 727°c (1341°f). (a) what is the proeutectoid phase? (b) h
vladimir2022 [97]
A. The proeutectoid phase is Fe₃c because 0.95 wt/c  is greater than the eutectoid composition which is 0.76 wt/c

b.  We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
The total cementite which is formed is 
(0.14) × (3.5kg) = 0.49kg

c.  We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
0.97 corresponds to mass.
W fe₃ C¹ = Ci - 0.76/5.94 = 0.03
∴ It is equivalent to 
(0.03) × (3.5) = 0.11kg of total of 3.5kg mass.
4 0
3 years ago
Imagine a car moving at a speed of 10 m/s it starts speeding up at an acceleration of 2 m/s/s. What will the car's speed be afte
alexandr402 [8]

Answer:

14 m/s

18 m/s

22 m/s

Explanation:

The car is moving at constant acceleration, so we can find its velocity at time t using the equation:

v=u+at

where

u = 10 m/s is the initial velocity

a=2 m/s^2 is the  acceleration

t is the time

Substituting the different times, we find:

At t = 2 s:

v=10+(2)(2)=14 m/s

At t = 4 s:

v=10+2(4)=18 m/s

At t = 6 s:

v=10+2(6)=22 m/s

6 0
3 years ago
Suppose that the Mars orbiter was to have established orbit at 155 km and that one group of engineers specified this distance as
MAXImum [283]

Answer:

108 km

Explanation:

The conversion factor between meters and feet is

1 m = 3.28 ft

So the second altitude, written in feet, can be rewritten in meters as

h_2 = 1.55 \cdot 10^5 ft \cdot \frac{1}{3.28 ft/m}=4.7\cdot 10^4 m

or in kilometers,

h_2 = 47 km

the first altitude in kilometers is

h_1 = 155 km

so the difference between the two altitudes is

\Delta h = 155 km - 47 km = 108 km

8 0
3 years ago
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