Answer:
Ф,
Ф
Explanation:
Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in terms of the length of the vector NNN and the angle θθtheta, with the components separated by a comma.
Vectors are quantities that have both magnitude and direction while scalar quantities have only magnitude but no direction.
This a vector quantity
from the diagram the horizontal component of the length of the vector will be
Ф
the vertical component will be
Ф
this is in the opposite direction because the x can be extrapolated to the negative axis
Answer:
5. -24 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
mathematically,
a = dv/dt ............................ Equation 1
Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.
But
v = dx(t)/dt
Where,
x(t) = 27t-4.0t³...................... Equation 2
Therefore, differentiating equation 2 with respect to time.
v = dx(t)/dt = 27-12t²............. Equation 3.
Also differentiating equation 3 with respect to time,
a = dv/dt = -24t
a = -24t .................... Equation 4
from the question,
At the end of 1.0 s,
a = -24(1)
a = -24 m/s².
Thus the acceleration = -24 m/s²
The right option is 5. -24 m/s²
One-dimensional motion can be plotted through the Cartesian plane which has a coordinates of (x,y). These coordinates are the abscissa and ordinates. Since, there are two coordinates, the answer to the second item is two.
The symbol that can be used to identify systems position is (x,y). Since this is one dimensional motion, it is possible that one of the two coordinates becomes zero.
To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.
By definition we know that
Where,
KE =Kinetic Energy
KR = Rotational Kinetic Energy
PE = Potential Energy
In this way
Where,
m = mass
v= Velocity
I = Moment of Inertia
Angular velocity
g = Gravity
h = Height
We know as well that 
for velocity (v) and Radius (r)
Therefore replacing we have
![[tex]h= \frac{1}{2} \frac{v^2}{g} +\frac{1}{2} \frac{I}{mg}(\frac{v}{r})^2](https://tex.z-dn.net/?f=%5Btex%5Dh%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bv%5E2%7D%7Bg%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7BI%7D%7Bmg%7D%28%5Cfrac%7Bv%7D%7Br%7D%29%5E2)
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Therefore the height must be 0.3915 for the yo-yo fall has a linear speed of 0.75m/s
Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
<u>v = 6.06 m/s</u>
