Answer:
0.002
Explanation:
The half-life of the radioactive nucleus is related to its quantity, by the following equation:

<u>Where:</u>
<em>N(t): is the quantity of the radioactive nucleus at time t</em>
<em>N₀: is the initial quantity of the radioactive nucleus</em>
<em>t: is the time = 4.5x10⁹ years</em>
<em>t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years</em>

Therefore, the fraction of the radioactive element in the rock today is 0.002.
I hope it helps you!
Answer:
if the car is traveling north, the person is also traveling north,
If the car turns to (left) to the west, the person will still tend to travel to the north and will slide to the right (north) on a slippery car seat.
A. The proeutectoid phase is Fe₃c because 0.95 wt/c is greater than the eutectoid composition which is 0.76 wt/c
b. We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
The total cementite which is formed is
(0.14) × (3.5kg) = 0.49kg
c. We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
0.97 corresponds to mass.
W fe₃ C¹ = Ci - 0.76/5.94 = 0.03
∴ It is equivalent to
(0.03) × (3.5) = 0.11kg of total of 3.5kg mass.
Answer:
14 m/s
18 m/s
22 m/s
Explanation:
The car is moving at constant acceleration, so we can find its velocity at time t using the equation:

where
u = 10 m/s is the initial velocity
is the acceleration
t is the time
Substituting the different times, we find:
At t = 2 s:

At t = 4 s:

At t = 6 s:

Answer:
108 km
Explanation:
The conversion factor between meters and feet is
1 m = 3.28 ft
So the second altitude, written in feet, can be rewritten in meters as

or in kilometers,

the first altitude in kilometers is

so the difference between the two altitudes is
