Answer:
heat used to rise temperature pan = 30.1%
heat used to rise temperature water = 69.9%
Explanation:
Given data
mass of water = 0.250 liter = 0.250 kg
aluminum pan mass = 0.500 kg
initial temperature = 20.0ºC
final temperature = 80.0ºC
to find out
heat used to rise temperature of pan and water
solution
we find here heat transferred to the water that is
heat transferred to the water = mass of water × specific heat of water × change in temperature ...........1
specific heat of water is 4186 J/kgºC
so
heat transferred to the water = 0.250 × 4186 × (80-20) kJ
heat transferred to the water = 62.8 kJ
and
heat transferred to the aluminum that is
heat transferred to the aluminum = mass of aluminum × specific heat of aluminum × change in temperature ...........2
here specific heat of aluminum is 900 J/kgºC
heat transferred to the aluminum = 0.500 × 900 × (80-20) kJ
heat transferred to the aluminum = 27 kJ
so
total heat = 62.8 + 27 = 89.8 kJ
so
heat used to rise temperature pan = 27/89.8 ×100% = 30.1%
heat used to rise temperature water = 62.8 / 89.8 ×100% = 69.9%
