Volumetric cylinders and volumetric flasks
Answer:
V = 5.83 m/s
Explanation:
Given that,
Mass of a ball of a clay, m = 2 kg
Initial speed of the clay, u = 35 m/s
Mass of a box, m' = 10 kg
Initially, the box was at rest, u' = 0
We need to find the velocity of the box after the collision. Let V be the common speed. Using the conservation of momentum to find it.
So, the velocity of the box after the collision is equal to 5.83 m/s.
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
This acceleration is directed towards the center of thecircle<span>. ... So for an object moving in a </span>circle<span>, there must be an inward </span>force<span> acting upon it in order to</span>cause<span> its inward acceleration. This is sometimes referred to as the </span>centripetal force<span> requirement.</span>
Answer:
block is being held in place on a frictionless surface. The block has a mass of 3.9 kg and is held in place on an incline of angle = 32° by a horizontal force F, as shown in the figure below.
Explanation:
