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____ [38]
3 years ago
15

The greater the mass of an object, the greater the _____. (fill in question) ​

Physics
2 answers:
yaroslaw [1]3 years ago
7 0
Momentum is the answer
g100num [7]3 years ago
4 0

Answer:

momentum

Explanation:

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A wave has a wavelength of 5m and frequency of 5 Hz. What is the speed of the wave?​
Anna71 [15]
If you multiply m (the unit for wavelength) with 1s (the unit for frequency), you will get m/s, the unit for speed. Now multiply! 25 m/s is your final answer!
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3. Differentiate between: (a) area and volume​
Margarita [4]

Answer:

area is 2d volume is 3d

Explanation:

Area refers to the size of two-dimensional surface. Volume refers to the size of a three-dimensional space.

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3 years ago
2. What do you understand by balanced and unbalanced force​
labwork [276]

Answer:

forces that are equal in size and opposite in direction. Balanced forces do not result in any change in motion. unbalanced. forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion.

\\

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8 0
2 years ago
35 miles North 6 feet down 136 MB 85 km SE
pantera1 [17]
The answer is 133 Se
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3 years ago
Read 2 more answers
Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the sun, a tungsten filament at 2
igomit [66]

Answer

Applying Wein's displacement

\lamda_{max}\ T = 2898 \mu_mK

1) for sun T = 5800 K

      \lambda_{max} = \dfrac{2898}{5800}

      \lambda_{max} = 0.5 \mu_m

2) for tungsten T = 2500 K

      \lambda_{max} = \dfrac{2898}{2500}

      \lambda_{max} = 1.16 \mu_m

3) for heated metal T = 1500 K

      \lambda_{max} = \dfrac{2898}{1500}

      \lambda_{max} = 1.93 \mu_m

4) for human skin T = 305 K

      \lambda_{max} = \dfrac{2898}{305}

      \lambda_{max} = 9.50 \mu_m

5)  for cryogenically cooled metal T = 60 K

      \lambda_{max} = \dfrac{2898}{60}

      \lambda_{max} = 48.3 \mu_m

range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ              0.01           0.4               0.7                 100

λT             58           2320            4060             5.8 x 10⁵

F                0             0.125             0.491                1

fractions

for UV = 0.125  

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509  

8 0
3 years ago
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