The cost c, in dollars, of a taxi ride is related to the

stira [4]

Ok so the answer is 160/32

4 0

2 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago

What is 2/3 times 7 wholes

Romashka-Z-Leto [24]

2/3 times 7 wholes is the same was 7 because 1 whole is 1.
What would you do it multiply the numerator and numerator so the would be 2x7. Then we would multiply the denominators. 3x1=1. Therefore the answer is 14/3.

6 0

3 years ago

A weather forecast states that there is a 20% probability of rain in the next three days. Describe a simulation you could perfor

iVinArrow [24]

Answer:

my hands hurt, pls give brainilist and hope this helps

Step-by-step explanation:

Before leaving for work, Victor checks the weather report in order to decide whether to carry an umbrella. The forecast is “rain" with probability 20% and “no rain" with probability 80%. If the forecast is “rain", the probability of actually having rain on that day is 80%. On the other hand, if the forecast is “no rain", the probability of actually raining is 10%.

1. One day, Victor missed the forecast and it rained. What is the probability that the forecast was “rain"?

2. Victor misses the morning forecast with probability 0.2 on any day in the year. If he misses the forecast, Victor will flip a fair coin to decide whether to carry an umbrella. (We assume that the result of the coin flip is independent from the forecast and the weather.) On any day he sees the forecast, if it says “rain" he will always carry an umbrella, and if it says “no rain" he will not carry an umbrella. Let U be the event that “Victor is carrying an umbrella", and let N be the event that the forecast is “no rain". Are events U and N independent?

3. Victor is carrying an umbrella and it is not raining. What is the probability that he saw the forecast?

3 0

3 years ago

What percentage is 28 min of 3 h. <br><br> Plssss explain too!!

Olegator [25]

Answer:

it's 15.5555555556%

Step-by-step explanation:

$28 \: min \: of \: 3h$