Answer:
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard
Step-by-step explanation:
70 company stores were investigared.
56 violated the institute's scanner accuracy standard.
70-56 = 14 did not violate the institute scanner accuracy standard.
If 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?
This is 14 divided by 70, so:
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard
The answer to that problem si 6-25+2x
Answer:
$
After 3 years
Step-by-step explanation:
Use I P R T it's a method for simple interest
I = Interest
P = Amount of money
R = Percent in decimal
T = Time in years
Answer:
I = 
(we dont know yet)
P = $
R = 
% 
T = 
Steps:
1. Set up your numbers with the method I P R T.
2. $65 will be your amount of money.
3. 7.5% needs to be converted because you will need to multiply later on in the problem. Simply move 2 places to the left to convert your percent into a decimal.
4. They want to know the total amount of money in his account at the end of 3 years. So 3 years will be your time in years.
5. After setting up your problem you need to multiply your Amount of money x percent as decimal x time in years.
6. After you find your interest you need to add your amount of money + interest.
Money after 3 years
hope this helped
<span>3|-3| = 3 * 3 = 9
answer is
9</span>
This problem can be solve by using
ration and proportion, since you want to enlarge the picture by not distorting
the image, the new dimensions should be in proportion with the old one.
Let x be length of the image
(5/40 = (x/5)
X = 5(5/4)
<span>X = 6.25 in</span>
