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azamat
2 years ago
5

a closed flask of air (0.250 L) contains 5.00 "puffs" of particles. The pressure probe on the flask reads 93 kPa. A student uses

a syringe to add an additional 3.00 "puffs" of air through the stopper. Find a new pressure inside the flask.
Chemistry
1 answer:
Sergio039 [100]2 years ago
3 0

Answer: New pressure inside the flask would be 148.8 kPa.

Explanation: The combined gas law equation is given by:

PV=nRT

As the flask is a closed flask, so the volume remains constant. Temperature is constant also.

So, the relation between pressure and number of moles becomes

P=n\\or\\\frac{P}{n}=constant

\frac{P_1}{n_1}=\frac{P_2}{n_2}

  • Initial conditions:

P_1=93kPa\\n_1=5\text{ puffs}

  • Final conditions: When additional 3 puffs of air is added

P_2=?kPa\\n_2=8\text{ puffs}

Putting the values, in above equation, we get

\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa

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Answer:

b) The volume of stock solution used is less than 3 liters.

Explanation:

Given:

Concentration of stock solution of NaCl, M1 = 10 M

Concentration of diluted solution of NaCl, M2 = 1 M

Volume of diluted NaCl solution, V2 = 3 L

Let the volume of stock NaCl solution = V1

Formula:

Use the dilution relation:

M1V1 = M2V2

Based on the above equation:

V1 = \frac{M2V2}{M1} = \frac{1M*3L}{10M} = 0.3 L

Therefore, the volume of stock solution required is 0.3 L which is less than 3 L

6 0
3 years ago
The work function for metallic potassium is 2.3 eV. Calculate the velocity in km/s for electrons ejected from a metallic potassi
mote1985 [20]

Answer:

932.44 km/s

Explanation:

Given that:

The work function of the magnesium = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, work function = 2.3\times 1.6022\times 10^{-19}\ J=3.68506\times 10^{-19}\ J

Using the equation for photoelectric effect as:

E=\psi _0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

Applying the equation as:

\frac {h\times c}{\lambda}=\psi _0+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

m is the mass of electron having value 9.11\times 10^{-31}\ kg

\lambda is the wavelength of the light being bombarded

\psi _0=Work\ function

v is the velocity of electron

Given, \lambda=260\ nm=260\times 10^{-9}\ m

Thus, applying values as:

\frac{6.626\times 10^{-34}\times 3\times 10^8}{260\times 10^{-9}}=3.68506\times 10^{-19}+\frac{1}{2}\times 9.11\times 10^{-31}\times v^2

3.68506\times \:10^{-19}+\frac{1}{2}\times \:9.11\times \:10^{-31}v^2=\frac{6.626\times \:10^{-34}\times \:3\times \:10^8}{260\times \:10^{-9}}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=7.64538\times 10^{-19}-3.68506\times 10^{-19}

\frac{1}{2}\times 9.11\times 10^{-31}\times v^2=3.96032462\times 10^{-19}

v^2=0.869446\times 10^{12}

v = 9.3244 × 10⁵ m/s

Also, 1 m = 0.001 km

<u>So, v = 932.44 km/s</u>

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3 years ago
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2 years ago
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Option D. Pollutants mix with air and water to make acid rain.

Option B. clay minerals and calcium carbonate

<h3>What is rusting?</h3>

Rusting is the process by which a metal especially reacts with oxygen in the atmosphere and water vapor to form a hydrated oxide of the metal known as hydrated iron (iii) oxide. This is known as rust.

The process is an oxidation process; option A.

<h3>How does air pollution impact chemical weathering?</h3>

Air pollution is the presence of substances in air known as pollutants which makes the air impure.

Air pollution impact chemical weathering  as the pollutants mix with air and water to make acid rain which weathers rocks; option D.

<h3>What products are produced when water reacts with sodium in rocks?</h3>

The reaction of water with sodium in rocks result in the formation of clay minerals and calcium carbonate also as limestone, marble or chalk; option B.

In conclusion, the presence of pollutants in air results in acid rain and hence rock weathering.

Learn more rock weathering at: brainly.com/question/2341950

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