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Aleksandr [31]
3 years ago
15

which of the following parts of a circuit would be considered a load ? Justify your answer by explaining your choices • light •

switch • motor • battery
Chemistry
1 answer:
QveST [7]3 years ago
6 0
The answer to the question given above is letter A. Light
 
Light  is considered a load of the parts of a circuit. <span>The load in a circuit can be any electrical device that converts electrical energy into other usable forms of energy such as a <span>light bulb.

>></span></span><span>Energy sources include batteries and generating stations
>>switch-</span><span>is used in electric circuits to allow the circuit to be turned on and off.</span>
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How many atoms are present in 7.50 mol of chlorine atoms? _
vodomira [7]

Answer:

4.52 x 10²⁴ atoms Cl

Explanation:

A mole is a name that means a certain number like a dozen means 12. 1 mole of chlorine atoms is 6.022 x 10²³ chlorine atoms. The unit conversion is 6.022 x 10²³/mol.

7.50molCl*\frac{6.022 x 10^{23} atomsCl}{1molCl} = 4.5165*10^{24} atomsCl

Round to 4.52 x 10²⁴ atoms Cl for the correct number significant figures.

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2 years ago
Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a h
makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: SiO_{2}+3C\rightarrow SiC+2CO

Molar mass of SiC = 40.11 g/mol

Molar mass of SiO_{2} = 60.08 g/mol

So, 100.0 kg of SiO_{2} = \frac{100.0\times 10^{3}}{60.08} moles of SiO_{2} = 1664 moles of SiO_{2}

According to balanced equation, 1 mol of SiO_{2} produces 1 mol of SiC

Therefore, 1664 moles of SiO_{2} produce 1664 moles of SiC

Mass of 1664 moles of SiC = (1664\times 40.11)g = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]\times 100%

                                 = \frac{51.4kg}{66.74kg}\times 100 %

                                 = 77.0%

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<em>b</em>

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