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4 years ago

7

If you push a 100-kilogram box on Earth, then take it to the Moon and try to push it there, it would feel like you were pushing

a _________-kilogram box
a. 16
b. 100
c. 160
d. 600

2 answers:

Vesna [10]4 years ago

8 0

A. i believe because the gravitational pull is stronger on earth than it is on the moon therefore making the box lighter than its original weight.

Sunny_sXe [5.5K]4 years ago

5 0

It would feel like your puching a 16 kilogram box

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How do you calculate voltage

IRINA_888 [86]

Voltage=Energy/Charge, V=E/Q V in volts V, E in joules J, Q in coulombs C. or Voltage= Current×Resistance, V=IR V in volts V, I in amperes A and R in ohms Ω

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3 years ago

A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the

adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

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4 years ago

A racing car whose mass is 1.2 X 10^3 kg is travelling at 8.9 m/s. It stops with a constant deceleration in a distance of 1.8X10

Alexeev081 [22]

given that initial speed of the car is

$v_i = 8.9 m/s$

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

$v_f^2 - v_i^2 = 2 a d$

$0 - 8.9^2 = 2 a d$

here we have

$- 79.21 = 2*(18)*a$

$a = -2.2 m/s^2$

net force applied due to brakes of car is given by Newton's II law

$F = ma$

here we have

mass = 1.2 * 10^3 kg

$F_{net} = 1.2 * 10^3 * 2.2$

$F_{net} = 2.64 * 10^3 N$

now we can say

$F_{net} = F_1 + F_2$

$2.64 * 10^3 = 1.8 * 10^3 + F_2$

$F_2 = 8.4 * 10^2 N$

So the force applied due to brakes is given as above

7 0

3 years ago

When an alkali metal is involved in a chemical reaction with a nonmetal, what charge will its atoms most likely form? 1- 2- 2+ 1

seraphim [82]

Answer:

+1 ion

Explanation:

Alkali metals are metals that are found in Group I of the periodic table. Their electronic configuration is such that their valence shell in grounds state is always holding only one electron which they always lose when reacting with non-metals. A loss in an electron makes the atom electrically imbalanced and hence becoming a +1 ion.

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3 years ago

A person yells across a canyon and hears an echo 2.5 seconds later. The air temperature is 21°C. How far away is the canyon wall

Alchen [17]

Answer: The canyon wall is 850 m away from the person

Explanation:

Well, the speed of sound $V$ in air at $21 \° C$ is defined as $343.60 m/s$ , this can be calculated by the following equation:

$V=\sqrt{\frac{\gamma R T}{M}}$ (1)

Where:

$\gamma=1.4$ is the Heat capacity ratio for air

$R=8.314 J/mol.K$ is the Universal Gas constant

$T=21 \° C+273.15=294.15 K$ is the temperature in Kelvin

$M=0.029 kg/mol$ is the air molar mass

$V=\sqrt{\frac{(1.4)(8.314 J/mol.K)(294.15 K)}{0.029 kg/mol}}$

$V=343.60 m/s$ (2)

Now that we know the speed of sound, we can use the following equation to find the distance between the person and the canyon wall:

$V=\frac{d}{t}$ (3)

Where:

$d$ is the distance between the person and the canyon wall

$t=2.5 s$ is the time it takes to the sound wave to travel from the person and then go back

Isolating $d$ :

$d=V.t$ (4)

$d=(343.60 m/s)(2.5 s)$ (5)

Finally:

$d=850 m$

7 0

3 years ago