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Zolol [24]
3 years ago
7

If you push a 100-kilogram box on Earth, then take it to the Moon and try to push it there, it would feel like you were pushing

a _________-kilogram box
a. 16
b. 100
c. 160
d. 600
Physics
2 answers:
Vesna [10]3 years ago
8 0
A. i believe because the gravitational pull is stronger on earth than it is on the moon therefore making the box lighter than its original weight.
Sunny_sXe [5.5K]3 years ago
5 0
It would feel like your puching a 16 kilogram box
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3 years ago
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An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented alo
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Answer:

The electric field strength at point (x,y) = ( 20 mm ,0cm) is =<u>16321.0769 N/C</u>

The electric field strength at point (x,y) = (0cm, 20 mm) is =<u>35321.58999 N/C</u>

Explanation:

Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?

Answer:

The electric field at any given point of the dipole is given as:

E= (KP) ÷ (r^2 + a^2)^3/2

Where:

K = 9x10^9 Nm^2/c^2 (coloumb constant)

P = (0.003) (5x10^-9c) which is the movement of the dipole

(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.

r= the point, in the question above is 20mm = 0.02m

Now, the electric field, E can be calculated by putting the values in the formula above:

E = (KP) ÷ (r^2 + a^2)^3/2

= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2

= 0.135 ÷ (8.271513x10^-6)

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 Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?

Answer:

Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2

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= 0.0054 ÷  0.000000152881

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8 0
2 years ago
Diamonds Choose one:
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Answer:

D. are brought from the mantle to the surface in magma that hardens into komatiite.

Explanation:

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Therefore the correct option for the diamond is D.

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3 years ago
What is the equation for an inelastic collision
abruzzese [7]
M1 v1 = (m1 + m2)v2.

All of the exponents should be lowered to the bottom right of the letters.
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3 years ago
What is the mass of an object that requires a force of 182 N to accelerate at a rate of 13 m/s?
Inga [223]

Answer:

m=14kg

Explanation:

Hello.

In this case, since the force is defined in terms of the mass and acceleration by:

F=m*a

We can easily compute the mass by solving for it:

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Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:

m=\frac{182kg\frac{m}{s^2} }{13\frac{m}{s^2}}\\\\m=14kg

Best regards.

6 0
3 years ago
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