If you push a 100-kilogram box on Earth, then take it to the Moon and try to push it there, it would feel like you were pushing
2 answers:
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Answer:
a) The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
Explanation:
a) From Second Newton's Law, we form this equation of equilibrium:
(Eq. 1)
Where:
- Electrostatic force exerted on human, measured in Newton.
- Weight of the human, measured in Newton.
If we consider that human can be represented as a particle and make use of definitions of electric field and weight, the previous equation is expanded and electric charge is cleared afterwards:
(Eq. 2)
- Electric field, measured in Newtons per Coloumb.
- Mass, measured in kilograms.
- Gravity acceleration, measured in meters per square second.
- Electric charge, measured in Coulomb.
As electric field of the Earth is directed in toward the center of the planet, that is, in the same direction of gravity, electric field must be a negative value. If we know that ,
and
, the charge that a 60-kg human must have to overcome weight is:
The magnitude of the electric charge that a 60-kg human must have to overcome weight is 3.923 coulombs and its sign is negative.
b) The electric force of repulsion between two people with the same charge calculated in part (a) is determined by Coulomb's Law, whose definition we proceed to use:
(Eq. 3)
Where:
- Electrostatic constant, measured in Newton-square meter per square Coulomb.
- Electric charge, measured in Coulomb.
- Distance between two people, measured in meters.
If we know that ,
and
, then the force of repulsion between two people is:
The force of repulsion between two people is newtons. The use of the earth's electric field a feasible means of flight is not feasible since electric force of repulsion would destroy human body before taking advantage of any possible flight skill.
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.