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natta225 [31]
3 years ago
15

Please,help me in question number 2 and 4.

\\ " alt="2and4 \\ " align="absmiddle" class="latex-formula">

Chemistry
1 answer:
svetoff [14.1K]3 years ago
8 0
I think it’s 890 I really don’t know
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During a change of state, the temperature of a substance _____.
Natali5045456 [20]
Hello,

Your questions states:

During a change of state, the temperature of a substance _____?

In which you gave us some choices:

A. decreases if the arrangement of particles in the substance changes.
B. remains constant until the change of state is complete.
C. increases if the kinetic energy of the particles in the substance increases.
D. increases during melting and vaporization and decreases during freezing and condensation.

Your answer would be:

B. remains constant until the change of state is complete.

Your explanation/Reasoning:

It absorbs the energy, then after the phase changes it then increases the temperature all over again.

Have a nice day:)

Hope this helps!

~Rendorforestmusic
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3 years ago
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Which lewis structures represent a molecule that would assume a linear geometry? check all that apply.
Daniel [21]
CO2, C2H2, BeF2, XeF2, etc all these molecules have linear geometry.
7 0
3 years ago
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300×175<br> Express your answer using the correct number of significant figures.
icang [17]

Answer:

300×175=52500

Explanation:

caculator

3 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
3 years ago
Someone please help me!!!!
Artyom0805 [142]

Double replacement :

2Na₃PO₄+3CaCl₂⇒6NaCl + Ca₃(PO₄)₂

<h3>Further explanation</h3>

1. A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds

2. Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

3. Combination/syntesis : 2 or more reactants combine to form a new compound

4. Decomposition : the reactant is decomposed into 2/more products

If we look at the reaction options available, all of them can be included in the double replacement reaction, but we only choose the reaction from Sodium phosphate and Calcium chloride which leads to options: C because it is balanced (from the number of atoms in the same reactant and product) and is in accordance with the chemical formula of each compound (both products and reactants)

3 0
3 years ago
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