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3 years ago

Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11

Chemistry

1 answer:

Leona [35]3 years ago

7 0

To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

M1 V1 = M2 V2

So from the formula, we will know how much volume of the 1.50 M we actually need.

1.50 M * V1 = 0.100 M * 350 mL

V1 = 23.33 mL

So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

350 mL – 23.33 mL = 326.67 mL water

Steps:

1. Take 23.33 mL of 1.50 M solution

<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M solution</span>

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tigry1 [53]

Answer:

We will expect 4 moles of MgO to be formed (option b).

Explanation:

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Step 2: Data given

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For 2 moles of magnesium consumed, we need 1 mole of oxygen to produce 2 moles of MgO.

For 4 moles of magnesium, we need 4/2 = 2 moles of oxygen.

For 4 moles of magnesium, we will produce 4/1 = 4 moles of MgO

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3 years ago

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Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

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Answer:

$\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}$

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Answer:

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