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fredd [130]
3 years ago
8

Bella observes that the gas-filled tire of her bicycle becomes a little deflated when she keeps the bicycle outside in cold weat

her. Which of the following laws is used to understand the behavior of the gas and why? The low temperature outside lowers the volume of the gas according to Charles's law because this law describes how a gas will behave at constant pressure. The low temperature outside increases the volume of the gas according to Charles's law because this law describes how a gas will behave at constant pressure. The low temperature outside lowers the volume of the gas according to Boyle's law because this law describes how a gas will behave when the number of moles remains constant. The low temperature outside increases the volume of the gas according to Boyle's law because this law describes how a gas will behave when the number of moles remains constant.
Chemistry
1 answer:
weqwewe [10]3 years ago
5 0

The low temperature outside lowers the volume of the gas according to Charles' law because this law describes how a gas will behave at constant pressure. It shows that the volume of a given mass of a gas is directly proportional to the absolute temperature provided the pressure remains constant. An increase in temperature leads to an increase in volume while a decrease reduces the volume. This is due to the reduction in the distances traveled by the vibrating  particles of the gas because of the lost kinetic energy.

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8 0
3 years ago
Read 2 more answers
If you weighed out 0.38 g of calcium and reacted it with an excess of hcl, how many moles of h2(g) would you expect to produce?
Hitman42 [59]
Answer is: 0,0095 mol of hydrogen gas will be produced in reaction.
Chemical reaction: Ca + 2HCl → CaCl₂ + H₂.
m(Ca) = 0,38 g.
n(H₂) = ?
n(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 0,38 g ÷ 40 g/mol
n(Ca) = 0,0095 mol.
from reaction: n(Ca) : n(H₂) = 1 : 1.
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n - amount of substance.
4 0
3 years ago
The element Oxygen, O, is an example of which of the following?
Anon25 [30]
It is an example of a molecule 
5 0
3 years ago
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Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of
jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = 2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x

2330.35x=1048815\\x=450.068g

Hence, there was 450.068g of water in the pot.

8 0
3 years ago
A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253
german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L

So, the new volume is 1.45 L.

6 0
3 years ago
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