First, we calculate the number of moles of each reactant using the formula:
Moles = mass / molecular weight
CaO:
Moles = 7.15/56 = 0.128
Water:
Moles = 152/18 = 8.44
The reaction equation shows that the reactants must be present in an equal number of moles, so CaO will be the limiting reactant and 0.128 mole of calcium hydroxide will form.
The energy released is given by:
Heat of reaction * number of moles
= -64.8 * 0.128
= -8.29 kJ
8.29 kJ of energy will be released
Answer:
a) 1.8 kJ
Explanation:
ΔG=-RtLnK
Just input the data into the equation to gives us the result, in Joules.
ΔG=-8.314*(25+273.15)*ln(0.48)
ΔG=1819,37 J
But there is only 2 significant figures, so we express it as or 1.8 kJ
C2H2O4 C2HO4- + H+
0.175 - x x x + y
C2HO4- c2o42– + H+
x - y y x + y
K2 = (y) (x +y) / (x-y)
As, y << x
So, K2 = (y) (x) / (x)
K2 = y =6.1 × 10^–5
Hence, concentration of (c2o42–) 6.1 × 10^–5 M