Question

What is the binding energy of an electron that requires a photon with a maximum wavelength of 430 nm to eject it? If a photon with a frequency of 8.21 x 1015 Hz is used, what is the kinetic energy of the electron?

Answer 1

Answer:

The kinetic energy of the electron is $4.98\times 10^{-18}\ J$.

Explanation:

Given that,

The maximum wavelength of a photon is 430 nm.

The frequency of a photon is $8.21\times 10^{15}\ Hz$

It is a case of photoelectric effect. The relation between the kinetic energy and the the work function as :

$K=hf-W_o\\\\K=hf-h\dfrac{c}{\lambda}\\\\K=h(f-\dfrac{c}{\lambda})\\\\K=6.63\times 10^{-34}\times (8.21\times 10^{15}-\dfrac{3\times 10^8}{430\times 10^{-9}})\\\\K=4.98\times 10^{-18}\ J$

So, the kinetic energy of the electron is $4.98\times 10^{-18}\ J$.