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Rudik [331]
3 years ago
12

During a care on level ground, Andra runs with an average velocity of 6.02 m/s to the East. What distance does Andra cover in 13

7 seconds?
Physics
1 answer:
garik1379 [7]3 years ago
4 0

Answer:

The distance covered is: 824.74 meters

Explanation:

Use the formula for velocity (v) as the distance (d) covered over the time (t) it took:

v = d / t

in our case:

6.02 m/s = d / 137 s

d = 6.02 * 137 = 824.74 meters

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Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle
Vinil7 [7]

Answer:

1/9 of that just outside the smaller sphere

Explanation:

The electric field strength produced by a charged sphere outside the sphere itself is equal to that produced by a single point charge:

E=k\frac{Q}{r^2}

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Calling R the radius of the first sphere, the electric field just outide the surface of the first sphere is

E_0=k\frac{Q}{R^2}

The second sphere has a radius which is 3 times that of the smaller sphere:

R'=3R

So, the electric field just outside the second sphere is

E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E_0}{9}

So, the correct answer is 1/9.

7 0
3 years ago
What happens to energy and matter when a wave moves through space?
vivado [14]

Answer:

energy can move from one location to another, the particles of matter in the medium return to their fixed position. A wave transports its energy without transporting matter.

4 0
3 years ago
The kinetic energy of a rotating body is generally written as K=12Iω2, where I is the moment of inertia. Find the moment of iner
stira [4]

Answer:

See explanation

Explanation:

We have a mass m revolving around an axis with an angular speed \omega, the distance from the axis is r. We are given:

\omega = 10 [rad/s]\\r=0.5 [m]\\m=13[Kg]

and also the formula which states that the kinetic rotational energy of a body is:

K =\frac{1}{2}I\omega^2.

Now we use the kinetic energy formula

K =\frac{1}{2}mv^2

where v is the tangential velocity of the particle. Tangential velocity is related to angular velocity by:

v=\omega r

After replacing in the previous equation we get:

K =\frac{1}{2}m(\omega r)^2

now we have the following:

K =\frac{1}{2}m(\omega r)^2 =\frac{1}{2}Iw^2

therefore:

mr^2=I

then the moment of inertia will be:

I = 13*(0.5)^2=3.25 [Kg*m^2]

3 0
3 years ago
A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
Read 2 more answers
What kind of waves are lasers worked by?
Andrew [12]

A laser is worked by electromagnetic radiation. The term "laser" originated as an acronym for "light amplification by stimulated emission of radiation".

4 0
3 years ago
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