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asambeis [7]
3 years ago
9

4.80-kg bucket of water is accelerated upward by a cord of negligible mass whose breaking strength is 75.0 N. If the bucket star

ts from rest, what is the minimum time required to raise the bucket a vertical distance of 12.0 m without breaking the cord?

Physics
2 answers:
ioda3 years ago
8 0

Answer:

Time,t=2.03seconds

Explanation:

Fg= 4.80×9.80= 47.04N

Maximum accelerating force= 75-47.04=27.96N

F= ma

27.96= 4.80 ×a

27.96/4.80=a

5.825m/s^2 =a

d=1/2at^2

d=12.0m

12=1/2 × 5.825 ×t^2

12 =2.913×t^2

t^2= 12/2.913

t= sqrt(4.120)

t= 2.03seconds

Finger [1]3 years ago
5 0

Explanation:

Below is an attachment containing the solution to the question.

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Answer:

Explanation:

Let the charge particle have charge equal to +q .

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force due to magnetic field = q ( v x B ) , v is velocity and B is magnetic field.

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The force will be along - ve y - direction .

If we take charge as negative or - q

force due to electric field will be along - y axis .

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3 years ago
Acceleration is defined as the rate of change for which characteristic?
Alenkasestr [34]

1) C. velocity

Acceleration is defined as the rate of change of velocity per unit time. In formulas:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the time interval

Therefore, the correct answer is C. velocity.


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Earth's gravity is a force, so it produces an acceleration on every object with mass located on the Earth's surface. This acceleration can be calculated, as it is given by the formula

g=\frac{GM}{r^2}

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G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

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By substituting these numbers into the formula, one can find that the acceleration due to Earth's gravity is g=9.81 m/s^2.

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4 years ago
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Gnesinka [82]

The orbiting velocity of the satellite is 4.2km/s.

To find the answer, we need to know about the orbital velocity of a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
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  • r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
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Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.

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Answer:

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Explanation:

The computation of speed is shown below:-

Here, The speed of the captain ship A report for speed of the ship B which is

S = \frac{S_A + S_B}{1 + \frac{(S_AS_B)}{c^2} }

where

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and

C indicates the velocity of life

now we will Substitute 0.40c for A and 0.60 for B in the equation which is

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after solving the above equation we will get

0.80 c

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