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3 years ago

Write a polynomial function of least degree with integral coefficients that has the given zeros. 4, -6, 1

Mathematics

1 answer:

german3 years ago

7 0

Answer: f(x) = x³ + x² - 26x + 24

<u>Step-by-step explanation:</u>

x = 4 x = -6 x = 1

x - 4 = 0 x + 6 = 0 x - 1 = 0

(x - 4) (x + 6) (x - 1) = 0

(x² + 2x - 24)(x - 1) = 0

x(x² + 2x - 24) -1(x² + 2x - 24) = 0

x³ + 2x² - 24x -x² - 2x + 24 = 0

x³ + x² - 26x + 24 = 0

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3 years ago

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3 years ago

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Order the integers {0, |-20|, -3, 19, -13} from least to greatest

tatiyna

Answer:

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3 years ago

Somebody, please help

SashulF [63]

F(x) can be written as:
f(x) = Asin(2x); where A is the amplitude and the period of the function is half that of a normal sin function.
f(π/4) = 4
4 = Asin(2(π/4))
4 = Asin(π/2)
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A for g(x) = 2
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5 0

3 years ago

In how many ways can the letters of the

GarryVolchara [31]

Answer: (b)

Step-by-step explanation:

Given

The letter "BHUTAN" has to be arranged

For filing the first place of 6 letter word, we have 6 choices

Similarly for filling the second place of the word, we have 5 choices as 1 letter is already filled.

In this way, the remaining places can be filled in 4, 3, 2, and 1 way

On combining the above, 6 places can be filled in

$\Rightarrow 6\times 5\times 4\times 3\times 2\times 1=6!\\\Rightarrow 720\ \text{ways}$

Thus, option (b) is correct.

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3 years ago