Answer:
FJ = 31.48N
Explanation:
In this case you have that the torque exerted by each, thumb and finger, over the point P, is equal and opposite by the torque exerted by each Jaw.
You equal one of the torque produced by your hand, as for example, the torque of the finger, with the torque produced by one jaw:
(1)
FF: finger force = 10.0N
FJ: jaw force = ?
d1: distance from finger to point P = 8.50cm = 0.085m
d2: distance form the border of the Jaws to the point P = 2.70cm = 0.027m
You solve the equation (1) for FJ and replace the values of the other parameters:
The force exerted by each jaw is 31.48N
Answer:
7.54 m/s
Explanation:
C = 2πr
C = 2π (0.450 m)
C = 2.827 m
v = d / t
v = 25.0 (2.827 m) / (9.37 s)
v = 7.54 m/s
Answer:
(c) position
Explanation:
From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.
But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e
W = F x d
This distance is a measure of the position of the body at a given instance.
Therefore, the work done is given by the force as a function of distance (or position).
The mass of the first block will be three times the mass of the second block.
According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;
F is the acting force
m is the mass
a is the acceleration of the body
Given the following parameters
Constant force F = 1N
For the first block with the acceleration of "a"
1 = m₁a
a = m₁/1
m₁ = a .................1
For the second block, acceleration is thrice that of the first. This means;
F = m(3a)
1 = 3ma
..........................2
Divide both equations
From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.
Learn more here: brainly.com/question/19030143
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