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3 years ago

What is the magnitude of the electrostatic force

Physics

2 answers:

Tresset [83]3 years ago

7 0

Answer:

2.3 x 10^-12

Explanation:

Plug into fe=kq1q2/r^2

ozzi3 years ago

5 0

The electron charge is called the Elementary Charge, given by:

$e=1.6*10^{-19}$

The Eletrostatic Force bewteen two changes is giver by Coulomb Law:

$F= \frac{Qqk}{d^2}$

Substituing the unknowns, we have:

$F= \frac{(1.6*10^{-19})^2}{(10^{-8})^2} \\ F=(1.6*10^{-11})^2 \\ \boxed {F=2.56*10^{-22}N}$

If you notice any mistake in my english, please let me know, because i am not native.

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All of the following are important reasons to take notes except.

jeka57 [31]

Its a waste of time, you have to not only write it down, but study it after too . other than that notes are great.

4 0

3 years ago

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Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm

faltersainse [42]

Answer:

1.35×10⁻⁷ m

37.278 mi/My

Explanation:

Speed of the tectonic plate= 6 cm/yr

Converting to seconds

$6=\frac{6}{365.25\times 24\times 60\times 60}$

So in one second it will move

$\frac{6}{365.25\times 24\times 60\times 60}$

In 71 seconds

$71\times \frac{6}{365.25\times 24\times 60\times 60}=1.35\times 10^{-5}\ cm$

The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m

Convert to mi/My

1 cm = 6.213×10⁻⁶ mi

1 M = 10⁶ years

$6\times 6.213\times 10^{-6}\times 10^6=37.278\ mi/My$

Speed of the tectonic plate is 37.278 mi/My

7 0

3 years ago

Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.

vagabundo [1.1K]

Answer:

R_total = 14.57 Ω , V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance

$R_{eq}$ = ∑ $R_{i}$

* For resistance in parallel

1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

R_B = Rb + R4

R_B = 2 + 18

R_B = 20 Ω

Branch C

R_C5 = Rc + R5

R_C5 = 3 + 12

R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

1 / R_BC = 1 / R_B + 1 / R_C5

1 / R_BC = 1/20 + 1/15 = 0.116666

R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

R_total = R_A + R_BC

R_total = 6 + 8.57

R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

10 = V_a + V_BC

10 = i R_a + i R_BC = i (R_a + R_BC)

i = 10 / (R_a + R_BC)

i = 10 / (14.57)

i = 0.6863 A

The current in the series circuit is constant

V_BC = i R_BC

V_BC = 0.6863 8.57

V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

Branch C

V_BC = i R_C5

i = V_BC / R_C5

i = 5.8819 / 15

i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

V_C = i R_C

V_C = 0.39213 3

V_C = 1.176 V

3 0

3 years ago

a race car is traveling at a speed of 80.0m/s on a circular race track of radius 450m what is the centripetal acceleration

slega [8]

Answer:

The answer of this question is =1.258*10-4

4 0

2 years ago

The average mass of a rhinoceros calf is 45 kg. What is its weight in newtons? Round your answer to the nearest whole number. 5

Thepotemich [5.8K]

Answer:

441 [N].

Explanation:

Weight=mass*g, where mass=45; g=9,8.

Weight=45*9.8=441 [N].

3 0

2 years ago

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