Assume <em>R</em> is measured in meters (m) and <em>M</em> in kilograms (kg). Then
<em>R</em> ² / (<em>GM</em>) = [m]² / ([N•m²/kg²] [kg]) = m•kg / N = m•kg / (kg•m/s²) = s²
so <em>t</em> ² is indeed proportional to <em>R</em> ²/(<em>GM</em>).
Use the Ideal Gas Law to the air in the tire :
( P ) ( V ) = ( n ) ( R ) ( T )
n = ( P ) ( V ) / ( R ) ( T )
P = P gauge + P baro = 31.2 psig + 14.8 psia = 46 psia
P = ( 46 psia ) ( 1 atm / 14.696 psia ) = 3.13 atm
n = ( P ) ( V ) / ( R ) ( T )
n = ( 3.13 atm ) ( 4.6 L ) / ( 0.08206 atm - L / mol - K ) ( 26.0 + 273.2 K )
n = 0.5864 moles
m = ( n ) ( M )
m = ( 0.5864 mol ) ( 28.96 g/ mol ) = 16.98 g
Its most likely C. Remember the bigger the vehicle the bigger the area it needs to make a safe turn.
Velocity is distance/time
so 150/7200=.0208km/s
unless you have to convert it to miles or something else. but use the formula!
