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Oxana [17]
3 years ago
7

Part E

Physics
2 answers:
Elodia [21]3 years ago
7 0

Answer:  

416,500 J – 67,200 J = 349,300 J

The potential energy at the top of the second hill is 349,300 joules.

miv72 [106K]3 years ago
4 0

Answer:

The potential energy at the top of the second hill is the potential energy at the top of the first hill minus the potential energy lost from friction:

416,500 J – 67,200 J = 349,300 J

The potential energy at the top of the second hill is 349,300 joules.

Explanation:

This answer came straight from the website of Edmentum.

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This assumes that the wave has velocity c (is light).

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How many kindergarteners do you think you can take on a fight before getting tired or over powered?
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The s.I unit of R so that the equation velocity= R × density S dimensionally correct R is a constant
Leviafan [203]

Answer:

R = m⁴/kg . s

Explanation:

In this case, the best way to solve this is working with the units in the expression.

The units of velocity (V) are m/s

The units of density (d) are kg/m³

And R is a constant

If the expression is:

V = R * d

Replacing the units and solving for R we have

m/s = kg/m³ * R

m * m³ / s = kg * R

R = m * m³ / kg . s

<h2>R = m⁴ / kg . s</h2>

This should be the units of R

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5 0
3 years ago
3. In 1989, Michel Menin of France walked on a tightrope suspended under a
Tamiku [17]

Answer: 80m

Explanation:

Distance of balloon to the ground is 3150m

Let the distance of Menin's pocket to the ground be x

Let the distance between Menin's pocket to the balloon be y

Hence, x=3150-y------1

Using the equation of motion,

V^2= U^s + 2gs--------2

U= initial speed is 0m/s

g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s

40m/s is contant since U (the coin is at rest is 0) hence V =40m/s

Slotting our values into equation 2

40^2= 0^2 + 2 * 10* (3150-y)

1600 = 0 + 63000 - 20y

1600 - 63000 = - 20y

-61400 = - 20y minus cancel out minus on both sides of the equation

61400 = 20y

Hence y = 61400/20

3070m

Hence, recall equation 1

x = 3150 - 3070

80m

I hope this solve the problem.

6 0
4 years ago
Which of the following forces can change the motion of an object? A. push B. shove C. pull D. all of these
Goshia [24]

Answer: The answer is D all of these sorry if i am wrong

Explanation:

3 0
3 years ago
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