All categories

3 years ago

How many grams of magnesium oxide can be produced when 125 g Mg react with 102 g O2?

1 answer:

3 0

The balanced chemical reaction is

<span>2Mg + O2 → 2MgO

To determine the amount of magnesium oxide produced from the reaction, we use the initial amount of the reactants and the relation of the substances from the reaction. We do as follows:

125 g Mg ( 1 mol / 24.31 g ) = 5.14 mol Mg
102 g O2 ( 1 mol / 32 g) = 3.19 mol O2

Therefore, the limiting reactant is magnesium. We calculate as follows:

5.14 mol Mg ( 2 mol MgO / 2 mol Mg ) ( 40.31 g /mol) = 207.19 g MgO produced.</span>

You might be interested in

Does anyone know how to do this?

Elanso [62]

Work out each and total up. hope this helped.

8 0

3 years ago

Which of the following changes to a pipe would increase the conductance by a factor of 12?

ivanzaharov [21]

C. Tripling the length and reducing the radius by a factor of 2 is the change to a pipe would increase the conductance by a factor of 12.

<u>Explanation:</u>

As we know that the resistance is directly proportional to the length of the pipe and it is inversely proportional to the cross sectional area of the pipe.

So it is represented as,

R∝ l /A [ area is radius square]

So k is the proportionality constant used.

R = kl/A

Conductance is the inverse of resistance, so it is given as,

C= 1/R.

R₁ = kl₁ / A₁

R₂ = kl₂/A₂

R₂/R₁ = 1/12 [∵ conductance is the inverse of resistance]

= l₂A₁ / l₁A₂

If we chose l₁/l₂= 3 and A₂/A₁= 4 So R₂/R₁= 1/3×4 = 1/12

So tripling the length and reducing the radius by a factor of 2 would increase the conductance by a factor of 12.

6 0

3 years ago

When a candle burns it produced 41,300 Joules per 1 gram. Use dimensional analysis to convert this to Calories per pound.

insens350 [35]

Answer:

4477381.7 calories/pound

Explanation:

It is given that,

When a candle burns it produced 41,300 Joules per 1 gram.

We need to convert it into calories per pound.

We know that,

1 cal = 4.184 J

⇒ 1 J = (1/4.184) cal

1 pound = 453.592 grams

⇒1 g = (1/453.592) pounds

Now,

$41300\ \text{Joules per gram}=\dfrac{41300\ \text{Joules}}{\text{gram}}\\\\=41300\times \dfrac{\dfrac{1}{4.184}\ \text{calories}}{\dfrac{1}{453.592}\ \text{gram}}\\\\=4477381.7\ \text{calories/pound}$

Hence, 41,300 Joules/gram = 4477381.7 calories/pound.

3 0

3 years ago

What is the human body's first line of defense against invading pathogens such as bacteria and viruses?

Sedbober [7]

ANTI---------- BODIES!!!!!!!

3 0

3 years ago

Calculate the mass of ZnCl2 produced by the reaction of 49.8 grams of H2. Zn + 2HCl ZnCl2 + H2

tester [92]

Answer:

3300.85 g

Explanation:

Given data:

Mass of ZnCl₂ produced = ?

Mass of H₂ produced = 49.8 g

Solution:

Chemical equation:

Zn + 2HCl → ZnCl₂ + H₂

Number of moles of H₂:

Number of moles = mass/molar mass

Number of moles = 49.8 g/ 2.056 g/mol

Number of moles = 24.22 mol

Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.

H₂ : ZnCl₂

1 : 1

24.22 : 24.22

Mass of ZnCl₂:

Mass = number of moles × molar mass

Mass = 24.22 × 136.286 g/mol

Mass = 3300.85 g

6 0

3 years ago