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Semmy [17]
3 years ago
14

When a candle burns it produced 41,300 Joules per 1 gram. Use dimensional analysis to convert this to Calories per pound.

Chemistry
1 answer:
insens350 [35]3 years ago
3 0

Answer:

4477381.7 calories/pound

Explanation:

It is given that,

When a candle burns it produced 41,300 Joules per 1 gram.

We need to convert it into calories per pound.

We know that,

1 cal = 4.184 J

⇒ 1 J = (1/4.184) cal

1 pound = 453.592 grams

⇒1 g = (1/453.592) pounds

Now,

41300\ \text{Joules per gram}=\dfrac{41300\ \text{Joules}}{\text{gram}}\\\\=41300\times \dfrac{\dfrac{1}{4.184}\ \text{calories}}{\dfrac{1}{453.592}\ \text{gram}}\\\\=4477381.7\ \text{calories/pound}

Hence, 41,300 Joules/gram = 4477381.7 calories/pound.

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2.5×10⁶ s

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From the question given above, the following data were obtained:

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Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

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The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti
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The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
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n = 28 / 4

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<h3>How to determine the fraction remaining </h3>
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Fraction remaining = N / N₀

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Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

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<em>Moles H₂S:</em>

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The volume could be obtained as follows:

PV = nRT

V = nRT / P

<em>V is volume in liters</em>

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<em>R is gas constant = 0.082atmL/molK</em>

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<em>P is pressure = 0.961atm</em>

<em />

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