0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
- p = pressure (atm)
- v = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
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C) Nucleus...... Hope it helps, Have a nice day :)
The reaction of sodium bromide with chlorine gas is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
<h3>What is sodium bromide?</h3>
Sodium bromide is an inorganic compound, white, crystalline with high melting point.
The reaction between halogens is redox reaction
Oxidation – 2Br⁻ ? Br₂ + 2e⁻ loss of electron.
Reduction – Cl₂ + 2e⁻ ? 2Cl⁻ gains of electron.
Thus, the correct option is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
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