All categories

4 years ago

The solubility of O2 in water is 0.590 g/L at an oxygen pressure of around 15.5 atm. What is the Henry's law constant for O2?

Chemistry

1 answer:

Lana71 [14]4 years ago

8 0

Answer: The Henry's constant for oxygen gas is $3.81\times 10^{-2}g/L.atm$

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{O_2}=K_H\times p_{O_2}$

where,

$K_H$ = Henry's constant = ?

$C_{O_2}$ = molar solubility of oxygen gas = $0.590g/L$

$p_{O_2}$ = partial pressure of oxygen gas = 15.5 atm

Putting values in above equation, we get:

$0.590g/L=K_H\times 15.5atm\\\\K_H=\frac{0.590g/L}{15.5atm}=3.81\times 10^{-2}g/L.atm$

Hence, the Henry's constant for oxygen gas is $3.81\times 10^{-2}g/L.atm$

You might be interested in

Given the standard heats of reaction

ANTONII [103]

Answer:

Explanation:

M(s) → M (g ) + 20.1 kJ --- ( 1 )

X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )

M( s) + 2 X₂(g) → M X₄ (g ) - 98.7 kJ ----- ( 3 )

( 3 ) - 2 x ( 2 ) - ( 1 )

M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s) → M X₄ (g ) - 98.7 kJ - 2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ

0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ

4 X (g ) + M (g ) = M X₄ (g ) - 773.4kJ

heat of formation of M X₄ (g ) is - 773.4 kJ

Bond energy of one M - X bond = 773.4 / 4 = 193.4 kJ / mole

6 0

3 years ago

Phuong trinh phan ung ohc cho +02

scZoUnD [109]

Answer:

yes

hope this helps!!!!

5 0

3 years ago

A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati

Katen [24]

Answer:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

Explanation:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

$Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}$

The pKa is

$-Log (Ka) = -Log (6.2x10^{-8}) = 7.2$

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.

3 0

4 years ago

Scurvy results in weakness in collagen fibers because the enzymes that catalyze ________ of proline and lysine residues in colla

ValentinkaMS [17]

Answer:

Hydroxylation

Explanation:

Hydroxylation is a chemical process that introduces a hydroxyl group (-OH) into an organic compound. In biochemistry, hydroxylation reactions are often facilitated by enzymes called hydroxylases. Hydroxylation is the first step in the oxidative degradation of organic compounds in air.

5 0

3 years ago

The _______ of a wave is a measure of the amount of energy it carries

Bumek [7]

The word that best fits is frequency. The sentence is The frequency of a wave is a measure of the amount of energy it carries. There is a direct relationship between frequency and energy of a wave. The constant of proportionality is h, Planck's constant. So, Energy = h * frequency. So, the answer is frequency. Although you should know that wavelength is related to frequency and so it is also a measure of the amount of energy and it should also be other valid answer.

6 0

3 years ago