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lana66690 [7]
4 years ago
15

What is the quotient of the complex number 4-3i divided by its conjugate?

Mathematics
1 answer:
almond37 [142]4 years ago
3 0

Answer: C. \frac{7}{25}-\frac{24}{25}i


Step-by-step explanation:

1. You have the following division:

\frac{4-3i}{4+3i} (As you can see, to find the conjugate of  4-3i you must change the sign between the terms).

2. To solve this division, you must multiply the numerator and the denominator by the conjugate of the denominator, as following:

=\frac{(4-3i)}{(4+3i)}\frac{(4-3i)}{(4-3i)}=\frac{16-12i-12i+9i^{2}}{16-9i^{2}}

3. Keeping on mind that i^{2}=-1, you have:

=\frac{16-12i-12i+9(-1)}{16-9(-1)}

4. Simplifying:

=\frac{7-24i}{25}=\frac{7}{25}-\frac{24}{25}i

5. The result is:

\frac{7}{25}-\frac{24}{25}i

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