Answer : The molarity of a solution is, 0.0337 M
Explanation : Given,
Mass of = 468 mg = 0.468 g (1 mg = 0.001 g)
Volume of solution = 50.0 mL
Molar mass of = 278 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the molarity of a solution is, 0.0337 M
Answer:
Mass FeCl2 = 0.0333g
Mass CrCl2 = 0.9961g
Explanation:
To solve this problem. The first equation we can write is:
Mass FeCl2 + Mass CrCl2 = 1.0294g <em>(1)</em>
Now, the Chlorides of FeCl2 and CrCl2 react producing 2.3609g of AgCl
Using molar mass of these species (126.75g/mol, 122.9g/mol, 143.32g/mol, respectively), you can write the equation:
2Mass FeCl2 / 126.75 + 2Mass CrCl2 / 122.9 = 2.3609/143.32
<em>That is: Moles Chloride before = Moles Chloride in AgCl after reaction</em>
7.8895x10⁻³Mass FeCl2 + 0.0162734MassCrCl2 = 0.016473 <em>(2)</em>
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Replacing (1) in (2):
7.8895x10⁻³ (1.0294g - MassCrCl2) + 0.0162734MassCrCl2 = 0.016473
8.12145x10⁻³ -7.8895x10⁻³MassCrCl2 + 0.0162734Mass CrCl2 = 0.016473
8.3839x10⁻³ MassCrCl2 = 8.35155x10⁻³
Mass CrCl2 = 0.9961g
And:
Mass FeCl2 = 1.0294g - 0.9961g
Mass FeCl2 = 0.0333g
The SI unit for the amount of substance present is the mole.
The mole is defined as the amount of substance that has the same amount of particles as there are atoms in 12 grams of carbon-12. Mathematically, the moles of a substance may be computed using:
moles present = mass of substance / molecular mass of substance
Answer:
0.0705 moles NaClO
Explanation:
<em>Assuming the bleach solution are 100mL:</em>
First, we need to find the mass of the solution knowing density = 1.0g/mL:
100mL * (1g/mL) = 100g
Then, we must find the mass of NaClO in 100g of solution using its percentage by mass:
100g * (5.25g NaClO / 100g) = 5.25g NaClO
As the last point, we need to convert the mass to moles using molar mass of NaClO = 74.44g/mol:
5.25g NaClO * (1mol/74.44g) = 0.0705 moles NaClO