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Alja [10]
3 years ago
12

Twenty irregular pieces of an unknown metal have a collective mass of 28.225 g. When carefully placed in a graduated cylinder th

at originally contained 7.75 mL of water, the final volume read 11.70 mL. What is the density of the metal (in g/cm3)?
Chemistry
1 answer:
Lelechka [254]3 years ago
8 0

Explanation:

Use the density formula to determine the volume of the piece of metal.

density

=

mass

volume

Rearrange the equation to isolate volume.

volume

=

mass

density

volume

=

147

g

7.00

g

mL

=

21.0 mL

The final volume in the cylinder after adding the piece of metal is

20.0 mL

+

21.0 mL

=

41.0 mL

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The  properties which keep the water temperature from changing much are;

  • water's high specific heat capacity
  • the large mass of water
<h3>What is specific heat capacity?</h3>

The specific heat capacity is the property of a substance that shows how much its temperature changes when it is exposed to heat.

Thus, the  properties which keep the water temperature from changing much are;

  • water's high specific heat capacity
  • the large mass of water

Missing parts:

A red-hot iron nail is immersed in a large bucket of water. Although the nail cools down sufficiently to be held bare-handed, the temperature of the water barely increases. Which properties keep the water temperature from changing much?

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C.) the iron nail's high heat conductivity

D.) the large mass of water

E.) the iron nail's high specific heat capacity

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2 years ago
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He noticed that similar elements were grouped together by using this.

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3 years ago
I just need 4-8! Plz hurry!!!!!!!!!!!
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8 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
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Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
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