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Alja [10]
4 years ago
12

Twenty irregular pieces of an unknown metal have a collective mass of 28.225 g. When carefully placed in a graduated cylinder th

at originally contained 7.75 mL of water, the final volume read 11.70 mL. What is the density of the metal (in g/cm3)?
Chemistry
1 answer:
Lelechka [254]4 years ago
8 0

Explanation:

Use the density formula to determine the volume of the piece of metal.

density

=

mass

volume

Rearrange the equation to isolate volume.

volume

=

mass

density

volume

=

147

g

7.00

g

mL

=

21.0 mL

The final volume in the cylinder after adding the piece of metal is

20.0 mL

+

21.0 mL

=

41.0 mL

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Gold has a density of about 20g/mL. If I measured out 2mL of gold, I would expect it to have a mass of about ___ grams.
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How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr
pickupchik [31]

Answer: There are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

Explanation:

Given : Volume = 7.62 L

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Pressure = 722 torr

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Converting torr into atm as follows.

722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

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T = temperature

Substitute the values into above formula as follows.

PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

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Thus, we can conclude that there are 1.469 \times 10^{23} molecules present in 7.62 L of CH_4 at 87.5^{o}C and 722 torr.

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3 years ago
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