Decreases as you move left to right
the RutherFord atomic model has the limitations in explaining the stability of the atom and the stability of the electron.
<u>Explanation:</u>
- As we know basically the atom comprises of the positively charged proton and negative charge electron and no charge neutron.
- In these particles, electron revolves with the nucleus as a centre in the orbit with the different energy levels.
- So by this revolving action, there will be the loss of energy and thus electrons are to be falling into the nucleus which affects the stability of the electron.
- The atom is said to be neutral electrically if the protons and electrons are equal. So in the above case if the electrons on losing the energy if it fells into the nucleus, as a result, the stability of the atom is affected which makes the atom as ions.
For a second order kinetics, the reaction rate expression would be
-r = -dCa / dt = kCa^2 where k is the reaction constant and Ca is the concentration of reactant A.
Integrating this from Cao to Caf, will have the expression,
1/Caf - 1/Cao = kt
Substituting the given values and calculating for k,
1/0.00650 - 1/0.0100 = k(100)
k = 0.538 / M-s
Answer:
A) 0.801
Explanation:
The reaction that takes place is:
- 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
First we c<u>alculate the H₂SO₄ moles that reacted</u>:
- 0.355 M * 28.2 mL = 10.011 mmol H₂SO₄
Now we <u>convert H₂SO₄ moles to NaOH moles</u>:
- 10.011 mmol H₂SO₄ *
= 20.022 mmol NaOH
Finally we <u>calculate the molarity of the NaOH solution</u>:
- 20.022 mmol NaOH / 25.0 mL = 0.801 M
So the answer is option A.
Data can arranged into visual displays called graphs. There are multiple types of graphs such as bar graphs, line graphs, scatter plots, and pie charts.
hopefully this helps :)