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aleksklad [387]
3 years ago
12

Which of the acyclic hydrocarbon series is represented by CnH2n​

Chemistry
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

alkenes

Explanation:

The general formula for alkenes is CnH2n

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What are the bonding states for the following materials? 1. Brass 2. Rubber 3. BaS 4. Solid xenon
MaRussiya [10]

Answer:

A chemical bond is defined as the force which helps to bind more than two atoms in a molecule. There are different types of chemical bonding are present in molecules such as:

1) Ionic bonding: Because of the transfer of electrons it is present in ionic compounds. BaS is an example of ionic bonding which is containing some covalent character.

2) Covenant bonding: Because of the sharing of electrons it forms molecules. Rubber is the example of covalent bonding with some van der walls.

3) Metallic bonding: In the free state it is present in atoms of metal such as Brass is a good example of a metallic bonding because it is a metal alloy.

4) Van der walls bonding: In atoms, It includes repulsion and attraction. Solid xenon is the example of Van der wall bonding because it is an inert gas.

7 0
3 years ago
Will a crayon dissolve in water?
sweet-ann [11.9K]

Answer:

Yes

Explanation:Like wax crayons but they can dissolve in water.

6 0
4 years ago
Read 2 more answers
16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution
nata0808 [166]

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= Volume\times density

= 1\times 1

= 1 \ kg

The mole of NaCl will be:

= \frac{mass}{Molar \ mass}

= \frac{25}{58.44}

= 0.43

hence,

The molarity will be:

= \frac{number \ of \ mole}{Volume \ of \ solution}

= \frac{0.43}{1}

= 0.43 \ M

The molality will be:

= \frac{mole \ of \ solute}{Weight \ of \ solvent}

= \frac{0.43}{1}

= 0.43 \ m

4 0
3 years ago
Calculate Srxn for the equation below. (Round to the nearest whole number.)
zaharov [31]

Answer:The the \Delta S_{rxn} for the given reaction is 179.98 J/K.

Explanation:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g),\Delta S_{rxn}=?

=192.8 J/mol K

\Delta S_{O_2}=205.0 J/mol K

\Delta S_{H_2O}=188.83 J/mol K

\Delta S_{NO}=210.8 J/mol K

\Delta S_{rxn}=(4 mol\times \Delta S_{NO}+6 mol\times \Delta S_{H_2O})-(4 mol\times \Delta S_{NH_3}-5 mol\times \Delta S_{O_2})

\Delta S_{rxn}=(4\times 210.8 J/mol K+6\times 188.83 J/mol K)-(4\times 192.8 J/mol K+5\times 205.0 J/mol K)

\Delta S_{rxn}=179.98 J/K

The the \Delta S_{rxn} for the given reaction is 179.98 J/K.

4 0
3 years ago
Please help, timed test, will give brainliest
OlgaM077 [116]

Answer:

The answer to your question is letter B

Explanation:

A.)                     2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

B.)                       2 AgCl + Na2S ⟶ Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         2

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           1

This reaction is balanced

C.)                         AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      1                         Ag                         4

                      1                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

D.)                2 AgCl + 2 Na2S ⟶ Ag2S + NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          1

                      4                          Na                         1

                      2                            S                          1

This reaction is unbalanced

4 0
3 years ago
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