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aleksklad [387]
3 years ago
12

Which of the acyclic hydrocarbon series is represented by CnH2n​

Chemistry
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

alkenes

Explanation:

The general formula for alkenes is CnH2n

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Is Boyle's law universally true? if not mention one of the its limitations​
murzikaleks [220]
Yes because look in the book dh
4 0
2 years ago
¿En qué grupo de sustancias químicas se incluye a la Hemoglobina?
olga2289 [7]

Answer:

"HEMOGLOBINA. Las características de la hemoglobina (Hb) como amortiguador están íntimamente vinculadas a la capacidad de disociación del grupo imidazólico del aminoácido histidina unido al hierro que contiene el grupo hemo (ver figura inferior)."

Link: http://www.ehu.eus/biomoleculas/buffers/buffer4.htm#:~:text=HEMOGLOBINA&text=Las%20caracter%C3%ADsticas%20de%20la%20hemoglobina,hemo%20(ver%20figura%20inferior).

3 0
3 years ago
50 pennies or other coins (all coins must be the same value)
Neko [114]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Question 1: <em>Turn 25 coins tails up. You now have 50% parent material and 50% daughter material. What is the half life of this substance? (20 Points)</em>


Answer:

Based upon the given information, we can assume that the half life of this coin material is 5 years.



Question 2: <em>Imagine that another half life has gone by. Remember that ONLY the parent material can change to the daughter material. Turn over your pennies to represent the passing of another half life. How much total parent material and how much total daughter material do you now have? You may express your answer in number of pennies or in %. (Note: Since you cannot turn over half a penny, round the actual number of pennies you would turn over up.) (20 points)</em>


Answer:

Based upon the given information from Question 2 and Question 3, we can assume that 13 additional coins would be turned over.  We started with 50, than flipped 50% of them over, and now another 50% over.  We have 12 coins left.



Question 3: <em>How many half lives will pass before you have only 3 pennies that are parent material and 47 pennies that are daughter material? (20 Points)</em>


Answer:

Based upon the given information from all the questions, and based upon our answers we can assume this:

1st half-life: 50 turned to 25 coins

2nd half-life: 25 turned to 12 coins

3rd half-life: 12 turns to 6 coins

4th half-life: 6 turns to 3 coins

So, after 4 half-lives (or after 20 years) we would have 3 coins left that have parent material.

------------------------------------------------------

<em>For future reference please do not post as complex questions like this, if you do (post a question that is similar to this) please state the following information:</em>

<em>"All questions posted in this post relate to one-another and cannot be answered without the other questions..."</em>

4 0
3 years ago
Let's consider a scenario in which the resting membrane potential changes from −70 mV to +70 mV, but the concentrations of all i
Inessa [10]

Answer: The correct answer is 1. outside and 2. inside.

Explanation:

During the resting potential (-70 mV), the concentration of Na+ is bigger outside than inside, so this situation generates a trend for moving inside. If we consider a scenario where the resting potential changes from -70 mV to +70 mV, we would realize that the electrical gradient would stop the entrance of Na+ ions and would make them to move outside.

6 0
3 years ago
A liquid mixture contains 1 kg of water, 1.9 lb of ethanol, and 4.6 lb of methyl acetate. What is the weight fraction of ethanol
slamgirl [31]

<u>Answer:</u> The weight fraction of ethanol in the mixture is

<u>Explanation:</u>

We are given:

Mass of water = 1 kg = 2.205 lb   (Conversion factor:  1 kg = 2.205 lb)

Mass of ethanol = 1.9 lb

Mass of ethyl acetate = 4.6 lb

Mass of mixture = [2.205 + 1.9 + 4.6] = 8.705 lb

To calculate the percentage composition of ethanol in mixture, we use the equation:

\%\text{ composition of ethanol}=\frac{\text{Mass of ethanol}}{\text{Mass of mixture}}\times 100

Mass of mixture = 8.705 lb

Mass of ethanol = 1.9 lb

Putting values in above equation, we get:

\%\text{ composition of ethanol}=\frac{1.9lb}{8.705lb}\times 100=21.8\%

Hence, the weight fraction of ethanol in the mixture is 21.8 %

4 0
3 years ago
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