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Daniel [21]
4 years ago
8

Which compound would produce an acidic aqueous solution? Which compound would produce an acidic aqueous solution? RbH C2H2 PH3 C

aH2 HF
Chemistry
2 answers:
Effectus [21]4 years ago
6 0

Answer:

HF

Explanation:

Anvisha [2.4K]4 years ago
4 0

Answer:  Option (e) is the correct answer.

Explanation:

A compound that will dissociate in water or an aqueous solution to give hydrogen ions(H^{+}) is known as an acidic substance.

When RbH is dissolved in aqueous solution then it dissociates as follows.

RbH \rightarrow Rb^{+} + H^{-}.

C_{2}H_{2} is non-polar in nature. So, it will not dissociate into ions when dissolved in an aqueous solution.

PH_{3} will also remain neutral and does not dissociate into ions.  

CaH_{2} when dissolved in water then it dissociates as follows.

CaH_{2} \rightarrow Ca^{2+} + 2H^{-}  

Whereas when HF is dissolved in aqueous solution then the reaction will be as follows.

HF \rightarrow H^{+} + F^{-}

Thus, we can conclude that out of the given options HF is the compound which will produce an acidic aqueous solution.

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When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox
kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen  using Lead (IV) oxide as a catalyst.

  1. The catalyst surface area is directly proportional to the reaction rate
  • So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

     2. Also, Removing lead (IV) oxide from the reaction mixture  the reaction rate decreased because as the catalyst is removed.

     3.  Using 50 cm³ of hydrogen peroxide  doesn't affect the rate because the concentration of the reactant doesn't change.

     4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0
4 years ago
A person who studies how sound waves move through water is involved in what branch of science? A. Space science O B. Life scienc
sladkih [1.3K]

Acoustics is a branch of physics that deals with the study of mechanical waves in gases, liquids, and solids including topics such as vibration, sound, ultrasound and infrasound.

6 0
3 years ago
Read 2 more answers
Which of the following soils is the most porous? Soil A - flat, sorted particles. Soil B - round, sorted particles Soil C - roun
Ksju [112]

Answer: Option (b) is the correct answer.

Explanation:

Porosity means the ease with which a fluid can pass through between a rock or cracks etc.

If particles of a soil are flat and even if they are sorted then there will rarely be any space available for fluid or water to pass through it.

If soil particles are round in shape and are sorted then there will be space available for the fluid to pass through it. Hence, this type of soil will be most porous.

Similarly, if soil particles are round but are unsorted then there will be less space available as compared to sorted particles. This is because particles are placed randomly so, somewhere there will be much less space and somewhere there will be large space available. As a result, soil will not be most porous.

If soil particles are flat and unsorted then there will also be less space available for the fluid to pass through it. Thus, soil will be less porous.

Hence, we can conclude that out of the given options, soil B - round, sorted particles is the most porous.

4 0
3 years ago
Somebody help please I'm really confused about the whole question.
zysi [14]
A 10.0g
ok hope this helps
5 0
3 years ago
Solid aluminum (Al) and chlorine (C1,) gas react to form solid aluminum chloride (A1CI2). Suppose you have 7.0 mol of Al and 1.0
WITCHER [35]

Answer:

6.3 moles

Explanation:

From the balanced equation of reaction:

2Al + 3Cl_2 --> 2AlCl_3

2 moles of aluminium reacts with 3 moles of chlorine gas to form 2 moles of AlCl3.

Therefore, 1 mole of chlorine will require: 2 x 1/3 = 0.67 mole of aluminium.

Hence, 0.67 mole of aluminium will be needed for 1 mole of chlorine. If 7 moles of aluminium is present, then:

   7 - 0.67 = 6.33 moles of aluminium will be left.

To the nearest 0.1, it means 6.3 moles of aluminium will be left.

4 0
3 years ago
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