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sineoko [7]
4 years ago
6

The use of brakes on a long, steep downgrade

Physics
1 answer:
Helen [10]4 years ago
7 0

Answer:

The correct answer is TRUE

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Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge
NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is V=\frac{1}{4\pi\epsilon} \frac{q}{d}

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as-E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero  between the two charges,but we can find the points situated on the axial  line but  outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining  two charges  where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0
3 years ago
L
nevsk [136]

Answer:

true

Explanation:

<h3><em>A healthy body will keep you in shape and less risk of getting sick</em></h3>
3 0
3 years ago
Which occupies mrs space, 3m cubed or 100ft cubed
Slav-nsk [51]

The question is somewhat ambiguous.

-- It's hard to tell whether it's asking about  '3 cubic meters'
or  (3m)³ which is actually 27 cubic meters.

-- It's hard to tell whether it's asking about    '100 cubic feet'
or  (100 ft)³ which is actually 1 million cubic feet.

I'm going to make an assumption, and then proceed to
answer the question that I have invented.
I'm going to assume that the question is referring to
'three cubic meters'  and  'one hundred cubic feet' .

OK.  We'll obviously need to convert some units here.
I've decided to convert the meters into feet.

For 1 meter, I always use    3.28084 feet.

Then (1 meter)³ = 1 cubic meter = (3.28084 ft)³ = 35.31 cubic feet.

So 3 cubic meters = (3 x 35.31 cubic feet) =  105.9 cubic feet.

That's more volume than  100 cubic feet.

6 0
3 years ago
Estimate the mass of blood in your body Explain your reasoning (Note: It is not enough to provide a numeric answer. The main poi
AVprozaik [17]

Answer: A little more that 5 Kg for a healthy person

Explanation: First, we know the following:

The regular adult has from 9 to 12 pints of blood. This is around 5 liters for a healthy male adult.

The human body is composed mostly on water, around 80%.

Blood is mostly composed on plasma, which makes blood thicker than water.

Knowing that, almost all the body is compose of water, it is safe to think that blood density should be near to that of water but higher.

The density on water is a know value. Which makes the following true:

<em>1 Liter of Water weights 1 Kg</em>

<em />

It could be said then, that the total mass of blood for a healthy person should be a little more that 5 kgs.

4 0
3 years ago
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg
kaheart [24]

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s

<u>v₂ = 4.2 m/s</u>

<u></u>

b)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)

<u>v₂ = 5 m/s</u>

5 0
3 years ago
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