24.0mm^3=24÷10÷10÷10cm^3
density=Mass÷Volume
Answer:
SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O
Explanation:
At first calculate the oxidation state of that element which undergoes oxidation as well as reduction.
for SO₄²⁻ the oxidation state of sulphur is +6 and H₂SO₃ the oxidation state of sulphur is +4
So balance equation is
(Reduction) SO₄²⁻ + 4H⁺+ 2e⁻ → H₂SO₃ + H₂O.........................................(1)
(oxidation) Sn²⁺ → Sn⁴⁺ + 2e⁻ .............................................................(2)
Adding equation 1 & 2
we get
SO₄²⁻(aq) +Sn²⁺(aq) +4H⁺ → H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O
Answer:
17.04 g/mol
Explanation:
Molar Mass of NH₃
we know that
Nitrogen has 14.01 gram/mol
And Hydrogen has 1.01 gram/mol
but we have 3 Hydrogens So we multiply
1.01 by 3 i.e., 3.03
Now, add
14.01
+<u> </u><u>3</u><u>.</u><u>0</u><u>3</u>
17.04
So, The molar mass of ammonia, NH₃ is
17.04 g/mol
<u>-TheUnknown</u><u>Scientist</u>
Answer:
<h2>Volume = 9.29 mL</h2>
Explanation:
Density of a substance can be found by using the formula
From the question
Density = 11.3 g/mL
mass = 105 g
Substitute the values into the above formula and solve for the volume
That's
Cross multiply
11.3v = 105
Divide both sides by 11.3
v = 9.29203
We have the final answer as
<h3>Volume = 9.29 mL</h3>
Hope this helps you
