When naming compounds, which type of compound uses prefixes to indicate the number of

1 answer:

6 0

Covalent bonds uses prefixes to indicate the number of atoms in the compound.
And example would be water which is dihydrogen monoxide, which means there are 2 hydrogen molecules and one oxygen molecule. The chemical formula would be H2O.

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Which terms describe plastics that can and potentially be recycled?

hammer [34]

C describes plastics that can be recycled. Thermoplastic can be remolded and reheated after forming, whereas thermoset strengthens when heated

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2 years ago

IF ANSWER I WILL GIVE BRAINLESS

vovikov84 [41]

Answer:

Answer 9 - 100 joules energy was at the producer level

Answer 10 - Remaining energy is used in metabolism

Explanation:

Answer 9

The energy at each trophic level is only 10% of the energy at its previous trophic level.

The energy at producer level is X

$10$ % of $X = 10$ Joules

$\frac{10}{100} * X = 10\\X = 100$ Joules

Answer 10

Because the remaining 90% energy is utilized by the producer for its metabolism

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2 years ago

The same reaction is begun with an initial concentration of 0.05 M O3 and 0.02 M NO. Under these conditions, the reaction reache

Ivahew [28]

The balanced equation of the reaction is:

O3(g) + NO (g) → O2 (g) + NO2 (g)

Then the ratios of reaction is 1 mol O3 : 1 mol NO : 1 mol O2 : 1 mol NO2

If you have initially 0.05 M of O3 and 0.02 M of NO, the reaction will end when all the NO is consumed.

The by the stoichiometry 0.02 mol of O3 will be consumed in 8 seconds.

And the rate of reaction is change in concetration divided by the time.

The change in concentration in O3 is 0.02 M

Then, the rate respect O3 is 0.02 M / 8 seconds = 0.0025 M/s

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3 years ago

Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:

12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: $n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}$