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Dvinal [7]
3 years ago
5

A 24.8 cm tall object is placed in

Physics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

Image distance, v = 4.67 cm

Explanation:

We have,

Height of the object, h = 24.8 cm

Height of the formed image, h' = -3.09 cm

Object distance, u - -37.5 cm

It is required to find the image distance. Lens formula is :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Using formula of magnification,

m=\dfrac{v}{u}=\dfrac{h'}{h}

v is image distance

v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ cm

So, the image distance is 4.67 cm.

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