Ask question

Ask question

All categories

Novosadov [1.4K]

3 years ago

6

The force of gravity is twice as great on a 2-kg rock as on a 1-kg rock. Why then, dose the 2-kg rock not fall with twice the ac

celleration?

1 answer:

Phoenix [80]3 years ago

8 0

Answer:

because all objects fall at a rate of 9.8m/s²

You might be interested in

I need this fast can you help me o give 12 points

Elanso [62]

Water as it's the highest specific heat capacity
Hope this helps x

7 0

3 years ago

Read 2 more answers

A ______________ is very general in nature, while a ________________ specifies what we want to study more specifically, suggesti

vova2212 [387]

Answer:

research topic and research question (hypothesis)

Explanation:

6 0

3 years ago

There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. A pilot fl

nikdorinn [45]

Answer:

Also 3s.

Explanation:

Each component is independent in two dimensional motion. This means that <em>how much time does something take to reach the ground when dropped is independent from any horizontal velocity</em>. If at one run a drop lasts 3s, at another run with twice the (horizontal) velocity and same height will also last 3s, no matter what.

8 0

3 years ago

When sedimentary rock is exposed to heat and pressure, what does it change into?

patriot [66]

Metamorphic rock this possess often occurs in the mantle

7 0

3 years ago

A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point

Mandarinka [93]

Answer:

$F=9.09\times 10^{-9} N$

Explanation:

We are given that

Mass of spherical shell, $m_1$ =1900 kg

Mass= $m_2=1.80 kg$

Radius of shell=r=5 m

Distance between two masses=r=5.01 m

Because distance measure from center .

Gravitational force

$F=G\frac{m_1m_2}{r^2}$

$G=6.67\times 10^{-11} Nm^2/kg^2$

Using the formula

$F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}$

$F=9.09\times 10^{-9} N$

Hence,the gravitational force = $F=9.09\times 10^{-9} N$

6 0

3 years ago