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slavikrds [6]
2 years ago
5

Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq

ual length. You then rub each with wool or on your hair so that the balloons hang apart with a noticeable separation between them. Make order-of-magnitude estimates of (b) the charge on each
Physics
1 answer:
Ulleksa [173]2 years ago
3 0

The charge on each the balloon is 100nC or 1.2 × 10^-7 C

Consider two balloons of diameter 0.200m each with a mass of 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical.

The charge on each balloon can be found from

F_{e} = \frac{k_{e}q^{2} }{r^{2}} \\q = \sqrt{\frac{k_{e}q^{2} }{r^{2}}} \\\\q = \sqrt{\frac{(2\times10^{-3N}(0.25m)^{2}}{8.99\times10^{9}N\cdotm^{2}/C^{2}}\\

q = 1.2\times10^{-7}C or 100nC

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. The matter is positively charged if it contains more protons than electrons and negatively charged if it contains more electrons than protons.

Learn more about the charge here:

brainly.com/question/14713274

#SPJ4

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In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6
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Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

                                      r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

                                      r₂= 7.5 cm

head upto water level is to rise = 60 + 5

                                          = 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q  

 π r₁² v₁ = π r₂² v₂  = 0.015

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{7.5^2}{5^2} v_2

 v_1= 2.25 v_2

 v_2 = \dfrac{0.015}{\pi r_2^2}

 v_2 = \dfrac{0.015}{\pi 0.075^2}

    v₂ = 0.848 m/s

    v₁ = 1.908 m/s

Applying Bernoulli's equation

 P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h

 P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65

 P_p= 635539.32 Pa

 P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

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4 years ago
Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located
Norma-Jean [14]

d.Both points have the same instantaneous angular velocity.

Explanation:

Let's analyze each option one by one:

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where \theta is the angular displacement and t is the time taken. Therefore, all the points rotate by the same angle \theta in the same time t.

b.Both points have the same centripetal acceleration.  --> FALSE. The centripetal acceleration of a point along the disk is given by

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c.Both points have the same tangential acceleration.  --> FALSE. The tangential acceleration is given by

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where \alpha is the angular acceleration. \alpha is the same for every point for a rigid body, but r is not (A is located farther away), so A and B do not have same tangential acceleration.

d.Both points have the same instantaneous angular velocity.  --> TRUE. This is true for what we said at point A).

e.Each second, point A turns through a greater angle than point B. --> FALSE. The two points cover the same angular displacement in the same time, since they have same angular velocity.

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