Question

If the maximum moment of force on a door is 10 Nm by an applied force of 2.25 N, then the distance of handle

Answer 1

Answer:

d = 4.44 m

Explanation:

Given that,

The moment of force on a door = 10 N-m

The applied force, F = 2.25 N

We need to find the distance of the handle. The moment of force is given by :

$\tau=F\times r$

Where

r is the distance of the handle.

$r=\dfrac{\tau}{F}\\\\r=\dfrac{10}{2.25}\\\\r=4.44\ m$

So, the required distance is equal to 4.44 m.