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lisov135 [29]
3 years ago
6

If the maximum moment of force on a door is 10 Nm by an applied force of 2.25 N, then the distance of handle

Physics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

d = 4.44 m

Explanation:

Given that,

The moment of force on a door = 10 N-m

The applied force, F = 2.25 N

We need to find the distance of the handle. The moment of force is given by :

\tau=F\times r

Where

r is the distance of the handle.

r=\dfrac{\tau}{F}\\\\r=\dfrac{10}{2.25}\\\\r=4.44\ m

So, the required distance is equal to 4.44 m.

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Four point charges are individually brought from infinity and placed at the corners of a square. Each charge has the identical v
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A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and
alex41 [277]

Answer:

The image is formed at 0.44 m in front of the mirror

magnification (M) = 0.44

Explanation:

Applying, mirror formular

1/f = (1/u)+(1/v).................... Equation 1

Where f = Focal length of the convex mirror, u = object distance, v = image distance.

Using the real is positive convection,

From the question,

Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m

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3 0
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