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lisov135 [29]
2 years ago
6

If the maximum moment of force on a door is 10 Nm by an applied force of 2.25 N, then the distance of handle

Physics
1 answer:
SVETLANKA909090 [29]2 years ago
4 0

Answer:

d = 4.44 m

Explanation:

Given that,

The moment of force on a door = 10 N-m

The applied force, F = 2.25 N

We need to find the distance of the handle. The moment of force is given by :

\tau=F\times r

Where

r is the distance of the handle.

r=\dfrac{\tau}{F}\\\\r=\dfrac{10}{2.25}\\\\r=4.44\ m

So, the required distance is equal to 4.44 m.

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a)  The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

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c) To minimize the distance traveled by the swimmer, his resultant velocity must be perpendicular to the velocity of the swimmer relative to water

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The downstream horizontal distance of the swimmer, x = v_{x} t

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