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Elan Coil [88]
4 years ago
14

Suppose the microphone on an AM radio is not working properly. Which best explains how this will affect the process of amplitude

modulation?
Physics
2 answers:
Anna007 [38]4 years ago
3 0
You can have it your own definition of
ratt3 years ago
0 0

on edg its C: Electrical signals will not be transformed into sound waves.

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A car with mass m traveling at speed v has kinetic energy k. what is the kinetic energy of a second car that has the same mass m
vampirchik [111]
Kinetic energy, KE, is modeled by the formula KE =  \frac{1}{2}mv^2, where m is the mass in kg and v is the velocity in m/s.

In this scenario, mass and one-half are constant but the velocity changes. 

You can see that by squaring twice the velocity, that is equal to four times the original KE. Therefore, the answer is 4k.
7 0
3 years ago
PLEASE HELPPP Count the number of atoms of each element in this molecule: 2H2K(OH2)2​
yulyashka [42]

Answer:

H = 6 atoms

K= 2 atoms

O = 2 atoms

7 0
3 years ago
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When one observes the phase of matter of water, one observes a property of matter.
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Which type of place is rich in biodiversity?​
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3 years ago
Underground water is being pumped into a pool whose cross section is 3 m x 4 m while water is discharged through a 0.076m-diamet
Svetllana [295]
Given:

Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min

Required:

Inlet flowrate

Solution:

The problem can be solved by this general formula.

Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

First, we need to convert the units of the accumulation velocity into m/s to be consistent.

Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s

We then calculate the area of the pool and the area of the orifice by:

Area of pool = 3 × 4 m²
Area of pool = 12m²

Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²

Since we have all we need, we plug in the values to the general equation earlier

Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice

0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²

Transposing terms,

Inlet flowrate = 0.316 m³/s
6 0
3 years ago
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