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What inertia is present in a stretched rubber?
1 answer:
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Answer:
the cart's speed at point B is 15.72 ft/s
Explanation:
Given the data in the question;
The car travels from point A to C in 3.00 s, its average acceleration will be;
= [
-
] / Δt
is 17.4 ft/s,
is 13.2 ft/s and Δt is 3.00 s
so we substitute
= [17.4 - 13.2] / 3
= 4.2 / 3
= 1.4 ft/s²
so average acceleration of the cart between the points A and B is 1.4 ft/s²
The instantaneous value of the velocity of the cart at point B will be;
= Δv / Δt
now substitute [ -
] for Δv and t' for Δt
= [
-
] / t'
=
-
( t' )
so we substitute 17.4 ft/s for , 1.20 s for t' and
= 1.4 ft/s²
= 17.4 - (1.4 × 1.20)
= 17.4 - 1.68
= 15.72 ft/s
Therefore, the cart's speed at point B is 15.72 ft/s