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KATRIN_1 [288]
3 years ago
7

What is the energy equivalent of 5.0 kg of mass? be sure to show all work to support your answer?

Physics
1 answer:
Dmitry [639]3 years ago
4 0
 The energy equivalent of 5.0 kg mass would be <span>4.5x10^17.</span>
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HELP PLS and HURRY
tangare [24]

Answer:

C - 50,000 * 77 * 3

Explanation:

At the top of the hill the potential energy is E= mgh= (160 kg)(9.81 m s^-2)(30 m)= 47088

hope it helps ,

<u>help me by marking as brainliest....</u>

5 0
2 years ago
Ángel is riding his bike 15m/h south a) speed b) velocity c) acceleration​
mixer [17]

Answer:

Velocity

Explanation:

Speed does not have a direction, Acceleration means that it is speeding up and not at a constant 15m/h, so the answer is B.

7 0
2 years ago
A 1.00-kg object is attached by a thread of negligible mass, which passes over a pulley of negligible mass, to a 2.00-kg object.
Anna [14]

Answer:

a = 3.27 m/s²

v = 2.56 m/s

Explanation:

given,

mass A = 1 kg

mass B = 2 kg

vertical distance between them = 1 m

F_d = mg

F_d = 2 \times 9.8

F_d = 19.6\ N

F_u = mg

F_u = 1 \times 9.8

F_u = 9.8\ N

F_{net} = 19.6 - 9.8

F_{net}=9.8\ N

F = (m_1+m_2)a

9.8 = (2+1)a

a = 3.27 m/s²

The speed of the system at that moment is:

v² = u² + 2×a×s

v² = 0² + 2× 3.27 × 1

v ² = 6.54

v = 2.56 m/s

3 0
3 years ago
A single crystal of a metal that has the FCC crystal structure is oriented such that a tensile stress is applied parallel to the
algol13

Stress required to cause slip on in the direction [ 1 1 0 ] is 7.154 MPa

<u>Explanation:</u>

Given -

Stress Direction, A = [1 0 0 ]

Slip plane = [ 1 1 1]

Normal to slip plane, B = [ 1 1 1 ]

Critical stress, Sc = 2.92 MPa

Let the direction of slip on = [ 1 1 0 ]

Let Ф be the angle between A and B

cos Ф = A.B/ |A| |B| = [ 1 0 0 ] [1 1 1] / √1 √3

cos Ф = 1/√3

σ = Sc / cosФ cosλ

For slip along [ 1 1 0 ]

cos λ = [ 1 1 0 ] [ 1 0 0 ] / √2 √1

cos λ = 1/√2

Therefore,

σ = 2.92 / 1/√3 1/√2

σ = √6 X 2.92 MPa = 2.45 X 2.92 = 7.154MPa

Therefore, stress required to cause slip on in the direction [ 1 1 0 ] is 7.154MPa

 

4 0
4 years ago
If a catcher catches a 0.5 kg baseball moving at 17.1 m/s in his glove, what is the average force in newtons on the glove during
aleksandr82 [10.1K]
The answer is attached.

7 0
3 years ago
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