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tatiyna
3 years ago
11

3. A model rocket is launched straight upward at 58.8 m/s.

Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Let us assume that rocket only runs in initial energy and not using its own to flying.

Also , let upward direction is +ve and downward direction is -ve .

Initial velocity , u = 58.8 m/s .

Acceleration due to gravity , g=-9.8\ m/s^2 .

Final velocity , v - = 0 m/s .

We know , by equation of motion .

v^2-u^2=2gh\\\\2gh_{max}=0^2-58.8^2\\\\h_{max}=\dfrac{0^2-58.8^2}{-2\times 9.8}\\\\h_{max}= 176.4\ m

Hence, this is the required solution .

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