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mario62 [17]
3 years ago
11

3.- Un barco que tiene el motor averiado es ayudado por dos remolcadores para entrar en el puerto. Cada uno de ellos tira de él

con una fuerza de 10000 N y ambas forman un ángulo de 60o. Calcula el módulo de la fuerza neta que actúa sobre el barco.
Physics
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

F_total = 10000 N

Explanation:

For this exercise we use that the force is a vector and the best way to do the sum is that since the two tugs pull the boat with the same intensity and angle, the sum of the component of the force perpendicular to the movement becomes zero.

The components parallel to the movement of the tugs is

            ∑ F = 2 Fcos θ

let's calculate

           F_total = 2 10000 cos 60

           F_total = 10000 N

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Answer:

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Vector C has magnitude 5.65 m and direction 210° from the +x-axis

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R = (Rₓî + Rᵧj) m

R = A + B + C = (7.01î + 5.28j) + (-5.84î + 5.84j) + (- 4.89î - 2.83j)

Summing the î and j components seperately,

R = (- 3.72î + 8.29j) m

To get its magnitude,

Magnitude of R = √(Rₓ² + Rᵧ²) = √((-3.72)² + (8.29)²) = 9.09 m

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