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mario62 [17]
3 years ago
11

3.- Un barco que tiene el motor averiado es ayudado por dos remolcadores para entrar en el puerto. Cada uno de ellos tira de él

con una fuerza de 10000 N y ambas forman un ángulo de 60o. Calcula el módulo de la fuerza neta que actúa sobre el barco.
Physics
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

F_total = 10000 N

Explanation:

For this exercise we use that the force is a vector and the best way to do the sum is that since the two tugs pull the boat with the same intensity and angle, the sum of the component of the force perpendicular to the movement becomes zero.

The components parallel to the movement of the tugs is

            ∑ F = 2 Fcos θ

let's calculate

           F_total = 2 10000 cos 60

           F_total = 10000 N

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An organ pipe open at both ends has a length of 0.80 m. If the velocity of sound in air is 340 m/s, what is the frequency of the
bazaltina [42]

Answer:

the frequency of the second harmonic of the pipe is 425 Hz

Explanation:

Given;

length of the open pipe, L = 0.8 m

velocity of sound, v = 340 m/s

The wavelength of the second harmonic is calculated as follows;

L = A ---> N   +  N--->N   +   N--->A

where;

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A represents antinode of the wave

N represents the node of the wave

L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda

The frequency is calculated as follows;

F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz

Therefore, the frequency of the second harmonic of the pipe is 425 Hz.

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