The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
Explanation:
The magnetic field strength at the center of a current-carrying circular loop is
where
is the vacuum permeability
I is the current
R is the radius of the loop
For the first circular loop, we have
The second loop has
(same current)
(twice the radius)
So, the magnetic field at the centre of the second loop is
So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
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The magnitude of the total displacement of her trip is 2.2 miles.
<h3>
Total displacement of Olivia's trip</h3>
The magnitude of the total displacement of her trip is calculated as follows;
Total east journey = 0.8 mi + 1.2 mi = 2 mi
Resultant displacement = √(y² + x²)
Resultant displacement = √(0.9² + 2²)
Resultant displacement = 2.2 mi
Thus, the magnitude of the total displacement of her trip is 2.2 miles.
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Mass does not change anywhere in the space .
So the given 30N is equal to the product of mass of the body and the acceleration due to gravity at that place in space.
After finding the mass of the body multiply it by the given acceleration due to gravity.
Mg is the approximate force due to gravity between the mass and the planet.
I hope this may help you.
Do you see that blank, open space after the word "potential ..." ?
There's supposed to be a number there that actually tells us the value of the potential. Without that number ... and a lot more description of the whole scenario here ... there's no possible answer to the question.
Via half-life equation we have:
Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes. By plugging those values in we get:
There is 6.25 grams left of Ra-229 after 12 minutes.
