A negative object so it takes in the charged object and nothing will happen until something else would touch it I think
The lateral displacement is I don’t know tbh I think 16.8
The volume of a cylinder is given by the formula v=pi r^2h, where r is the radius of the cylinder and h is the height.
<h3>What Does a Cylinder's Surface Area Look Like?</h3>
The overall area or region that the surface of a cylinder covers is referred to as its surface area. A cylinder's total surface area includes both the area of the curved surface and the area of the two flat surfaces because there are two flat surfaces and one curved surface. A cylinder's surface area is measured in square units like m2, in2, cm2, yd2, etc.
<h3>What is the cylinder's total surface area?</h3>
The sum of the curved surface areas makes up the cylinder's overall surface area.
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Answer:
The Milky Way is about 1,000,000,000,000,000,000 km (about 100,000 light years or about 30 kpc) across. The Sun does not lie near the center of our Galaxy. It lies about 8 kpc from the center on what is known as the Orion Arm of the Milky Way
Answer:
i 5.3 cm ii. 72 cm
Explanation:
i
We know upthrust on iron = weight of mercury displaced
To balance, the weight of iron = weight of mercury displaced . So
ρ₁V₁g = ρ₂V₂g
ρ₁V₁ = ρ₂V₂ where ρ₁ = density of iron = 7.2 g/cm³ and V₁ = volume of iron = 10³ cm³ and ρ₂ = density of mercury = 13.6 g/cm³ and V₂ = volume of mercury displaced = ?
V₂ = ρ₁V₁/ρ₂ = 7.2 g/cm³ × 10³ cm³/13.6 g/cm³ = 529.4 cm³
So, the height of iron above the mercury is h = V₂/area of base iron block
= 529.4 cm³/10² cm² = 5.294 cm ≅ 5.3 cm
ρ₁V₁g = ρ₂V₂g
ii
ρ₁V₁ = ρ₃V₃ where ρ₁ = density of iron = 7.2 g/cm³ and V₁ = volume of iron = 10³ cm³ and ρ₃ = density of water = 1 g/cm³ and V₃ = volume of water displaced = ?
V₃ = ρ₁V₁/ρ₃ = 7.2 g/cm³ × 10³ cm³/1 g/cm³ = 7200 cm³
So, the height of column of water is h = V₃/area of base iron block
= 7200 cm³/10² cm² = 72 cm
