Explanation:
The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

At t = 1 s,
Current,

So, the current at t = 1 s is 3 A.
For lowest current,

Hence, this is the required solution.
  
        
             
        
        
        
To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find



learn more about potential difference from here: brainly.com/question/28166044
#SPJ4
 
        
             
        
        
        
A. less than
In fact, the resistance will be less than that of the lowest resistance resistor.
        
                    
             
        
        
        
The power delivered to the coil is 0.5 Watts
<h3>Resistivity of a material</h3>
The formula for calculating the power delivered to it is expressed according to the equation
Power = I²R
where
I is the current
R is the resistance
Given
Current = 0.500A
Determine the resistance using the resistivity formula
R = ρL/A
Substitute the given parameters
R = 10^-6*(25)/0.002²
R = 2ohms
Substitute
Power = I²R
Power = (0.5)²(2)
Power = 0.5watts
Hence the power delivered to the coil is 0.5 Watts
Learn more on resistivity here: brainly.com/question/17010736
#SPJ4
 
        
             
        
        
        
The velocity at point B is 10 m/s with a pressure of 262500 Pa
<h3>
Bernoulli equation</h3>
According to the continuity equation:
A₁V₁ = A₂V₂
Where A is the area and V is velocity, ρ = density of water = 1000 kg/m³
Hence:
4(5) = 2(V₂)
V₂ = 10 m/s
Using Bernoulli equation:

The velocity at point B is 10 m/s with a pressure of 262500 Pa
Find out more on Bernoulli equation at: brainly.com/question/14082066