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3 years ago

8

When you see your image on the surface of the water in a pond, which phenomenon is at work?

2 answers:

Svetlanka [38]3 years ago

8 0

Answer:

Specular reflection

Explanation:

It is produced in very flat reflective surfaces as with mirrors. In this case the reflection takes place in only one direction thanks to which it is possible to form images. This type of reflection obeys the law of reflection, so the angle of incidence of the rays is equal to the angle of reflection.

Lemur [1.5K]3 years ago

5 0

Answer: The correct answer is "Reflection".

Explanation:

Reflection is the phenomenon in which the light ray gets reflected from the surface without getting transmit or absorb. It bounces back from the surface.

There are two laws of reflection.

(1) The angle of reflection is equal to the angle of incidence.

(2) The reflected ray, the incident ray and the normal lie in the same plane.

When you see your image on the surface of the water in a pond, the reflection phenomenon is at work.

Therefore, the correct answer is "Reflection phenomenon".

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A single loop of wire with an area of 0.0780 m2 is in a uniform magnetic field that has an initial value of 3.80 T, is perpendic

Katarina [22]

Answer:

The induced current is 26.7 mA

Explanation:

Given;

area of the loop, A = 0.078 m²

initial magnetic field, B₁ = 3.8 T

change in the magnetic field strength, dB/dt = 0.24 T/s

The induced emf is calculated as;

$emf = - \frac{d \phi}{dt} \\\\emf = -\frac{dB.A}{dt} \\\\emf = A (\frac{dB}{dt} )\\\\emf = 0.078(0.24)\\\\emf = 0.0187 \ V$

The resistance of the loop = 0.7 Ω

The induced current is calculated as;

$V = IR\\\\I = \frac{V}{R} = \frac{emf}{R} = \frac{0.0187}{0.7} = 0.0267 \ A = 26.7 \ mA$

4 0

3 years ago

When sunlight shines on a leaf the leaf looks green why does the leaf look green

KonstantinChe [14]

The correct answer is the third, It reflects the green light waves and absorbs most of the rest.

7 0

3 years ago

Read 2 more answers

A 14.0 gauge copper wire of diameter 1.628 mm carries a current of 12.0 mA . A) What is the potential difference across a 1.80 m

Serga [27]

Answer: a) 139.4 μV; b) 129.6 μV

Explanation: In order to solve this problem we have to use the Ohm law given by:

V=R*I whre R= ρ *L/A where ρ;L and A are the resistivity, length and cross section of teh wire.

Then we have:

for cooper R=1.71 *10^-8* 1.8/(0.001628)^2= 11.61 * 10^-3Ω

and for silver R= 1.58 *10^-8* 1.8/(0.001628)^2=10.80 * 10^-3Ω

Finalle we calculate the potential difference (V) for both wires:

Vcooper=11.62* 10^-3* 12 * 10^-3=139.410^-6 V

V silver= 10.80 10^-3* 12 * 10^-3=129.6 10^-6 V

8 0

3 years ago

Read 2 more answers

A 1,650 kg SUV comes uniformly to a stop. If the vehicle is accelerating at -1.3 m/s^2,

lions [1.4K]

Answer:b

Explanation:

4 0

3 years ago

A circuit contains a 1.5 volt battery and a bulb with a resistance of 3 ohms. Calculate the current

Vitek1552 [10]

The formula that links voltage (V), resistance (R) and current intensity (I) is

$V=RI$

Solve this formula for I to get

$I=\dfrac{V}{R}$

Plug your values for V and R and you'll get the current.

8 0

3 years ago