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4 years ago

When you see your image on the surface of the water in a pond, which phenomenon is at work?

Physics

2 answers:

Svetlanka [38]4 years ago

8 0

Answer:

Specular reflection

Explanation:

It is produced in very flat reflective surfaces as with mirrors. In this case the reflection takes place in only one direction thanks to which it is possible to form images. This type of reflection obeys the law of reflection, so the angle of incidence of the rays is equal to the angle of reflection.

Lemur [1.5K]4 years ago

5 0

Answer: The correct answer is "Reflection".

Explanation:

Reflection is the phenomenon in which the light ray gets reflected from the surface without getting transmit or absorb. It bounces back from the surface.

There are two laws of reflection.

(1) The angle of reflection is equal to the angle of incidence.

(2) The reflected ray, the incident ray and the normal lie in the same plane.

When you see your image on the surface of the water in a pond, the reflection phenomenon is at work.

Therefore, the correct answer is "Reflection phenomenon".

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A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc

guajiro [1.7K]

Answer:

$0.005734 s^{-1}$ and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

$a_o=a\times e^{-kt}$

where,

k = rate constant

t = age of sample

$a_o$ = let initial amount of the reactant

a = amount left after decay process

We have :

$a_o=x$

$a=58\%\times x=0.58x$

t = 95 s

$0.58x=x\times e^{-k\times 95 s}$

$\k= 0.005734 s^{-1}$

Half life is given by for first order kinetics::

$t_{1/2}=\frac{0.693}{k}$

$=\frac{0.693}{0.005734 s^{-1}}=120.86 s$

$0.005734 s^{-1}$ and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

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3 years ago

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Basile [38]

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3 years ago

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What are three physical properties of gases

NikAS [45]

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Explanation:

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3 years ago

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katrin [286]

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3 years ago

When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When

Gemiola [76]

Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, $\dfrac{dI}{dt}=0.0240\ A/s$