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Marianna [84]
3 years ago
5

Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?​

Physics
2 answers:
telo118 [61]3 years ago
6 0
  • Force=12N
  • Work=9J

\\ \sf\longmapsto W=Fd

\\ \sf\longmapsto d=\dfrac{W}{F}

\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m

GrogVix [38]3 years ago
6 0

Answer:

Anne pushed a cart by 12 N.

● Force = 12 N

Work done is 9 J

● Work = 9 J

=> Work = Force × distance

=> distance =  \frac{work}{force}

=> distance =  \frac{9}{2}

=> distance = 0.72m

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AleksandrR [38]

a) 5.0 m/s

This first part of the problem can be solved by using the conservation of energy. In fact, the mechanical energy of the girl just after she jumps is equal to her kinetic energy:

E_i=\frac{1}{2}m_1v_1^2

where m1 = 60 kg is the girl's mass and v1 = 8.0 m/s is her initial velocity.

When she reaches the height of h = 2.0 m, her mechanical energy is sum of kinetic energy and potential energy:

E_f = \frac{1}{2}m_1 v_2 ^2 + m_1 gh

where v2 is the new speed of the girl (before grabbing the box), and h = 2.0m. Equalizing the two equations (because the mechanical energy is conserved), we find

\frac{1}{2}m_1 v_1^2 = \frac{1}{2}m_1 v_2 ^2 + m_1 gh\\v_1^2 = v_2^2 +2gh\\v_2 = \sqrt{v_1^2 -2gh}=\sqrt{(8.0 m/s)^2-(2)(9.8 m/s^2)(2.0 m)}=5.0 m/s

b) 4.0 m/s

After the girl grab the box, the total momentum of the system must be conserved. This means that the initial momentum of the girl must be equal to the total momentum of the girl+box after the girl catches the box:

p_i = p_f\\m_1 v_2 = (m_1 + m_2) v_3

where m2 = 15 kg is the mass of the box. Solving the equation for v3, the combined velocity of the girl+box, we find

v_3 = \frac{m_1 v_2}{m_1 + m_2}=\frac{(60 kg)(5.0 m/s)}{60 kg+15 kg}=4 m/s

c) 2.8 m

We can use again the law of conservation of energy. The total mechanical energy of the girl after she catches the box is sum of kinetic energy and potential energy:

E_i = \frac{1}{2}(m_1+m_2) v_3^2 + (m_1+m_2)gh=\frac{1}{2}(75 kg)(4 m/s)^2+(75 kg)(9.8 m/s^2)(2.0m)=2070 J

While at the maximum height, the speed is zero, so all the mechanical energy is just potential energy:

E_f = (m_1 +m_2)gh_{max}

where h_max is the maximum height. Equalizing the two expressions (because the mechanical energy must be conserved) and solving for h_max, we find

E_i = (m_1+m_2)gh_{max}\\h_{max}=\frac{E_i}{(m_1+m_2)g}=\frac{2070 J}{(75 kg)(9.8 m/s^2)}=2.8 m

4 0
3 years ago
Which part of the ear receives the signal from the eardrum?​
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Answer:

Ossicles

Explanation:

Sound causes eardrums to vibrate. These vibrations are then passed on to the ossicles, which is made up of 3 small bones-- the malleus, incus, and stapes. The stapes are connected to the inner ear, specifically to the cochlea which transforms sound waves into electrical signals that are sent to the brain.

7 0
3 years ago
A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.
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Answer:

Height of tree = 78.35 meters.

Explanation:

We have

          1 meter = 3.28 feet

That is

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Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

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