Answer:
T=1022.42 N
Explanation:
Given that
l = 32 cm ,μ = 1.5 g/cm
L =2 m ,V= 344 m/s
The pipe is closed so n= 3 ,for first over tone
f= 129 Hz
The tension in the string given as
T = f²(4l²) μ
Now by putting the values
T = f²(4l²) μ
T = 129² x (4 x 0.32²) x 1.5 x 10⁻³ x 100
T=1022.42 N
Answer:
1.6 x 10⁻⁶ J/m³
Explanation:
I = Intensity of electromagnetic radiation = 475 Wm⁻²
U = average total energy density of electromagnetic radiation
c = speed of electromagnetic radiation = 3 x 10⁸ m/s
Intensity of electromagnetic radiation is given as
Inserting the values
U = 1.6 x 10⁻⁶ J/m³
Answer:
Explanation:
given,
initial speed of the shot = 12.0 m/s
angle = 40°
height at which shot leaves her hand = 1.80 m
v_x = 12 cos 40° = 9.19 m/s
v_y = 12 sin 40° = 7.71 m/s
time to reach maximum height =
=
=
= 0.787 s
h = 7.71 × 0.787 - 0.5 × 9.81 × 0.787²
h = 3.03 m
the maximum height attain = 3.03 + 1.8 = 4.83 m
now free fall from the maximum height
t = 0.9928 s
total time = 0.9928 + 0.787 = 1.7798 s
range =
d = vₓ t
d = 16.36 m